javafx：如何将 Enter 键绑定到按钮并在单击时触发事件？
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javafx: How to bind the Enter key to a button and fire off an event when it is clicked?
提问by mynameisJEFF
Basically, I have a okayButtonthat sits in a stageand when it is clicked , it performs a list of tasks. Now I want to bind the Enterkey to this button such that when it is clicked OR the ENTER key is pressed, it performs a list of tasks.
基本上，我有一个okayButton位于 a 中stage，当它被点击时，它会执行一个任务列表。现在我想将Enter键绑定到这个按钮，这样当它被点击或按下 ENTER 键时，它会执行任务列表。
okayButton.setOnAction(e -> {
.........
}
});
How can I do that ? I have read the following postalready. However, it did not help me to achieve what I want to do.
我怎样才能做到这一点 ？我已经阅读了以下帖子。然而，它并没有帮助我实现我想做的事情。
采纳答案by Dici
First, set a hanlder on your button :
首先，在您的按钮上设置一个处理程序：
okayButton.setOnAction(e -> {
......
});
If the button has the focus, pressing Enterwill automatically call this handler. Otherwise, you can do this in your startmethod :
如果按钮具有焦点，按Enter 键将自动调用此处理程序。否则，您可以在您的start方法中执行此操作：
@Override
public void start(Stage primaryStage) {
// ...
Node root = ...;
setGlobalEventHandler(root);
Scene scene = new Scene(root, 0, 0);
primaryStage.setScene(scene);
primaryStage.show();
}
private void setGlobalEventHandler(Node root) {
root.addEventHandler(KeyEvent.KEY_PRESSED, ev -> {
if (ev.getCode() == KeyCode.ENTER) {
okayButton.fire();
ev.consume();
}
});
}
If you have only one button of this kind, you can use the following method instead.
如果你只有一个这样的按钮，你可以用下面的方法代替。
okayButton.setDefaultButton(true);
回答by armin.miedl
I've had the same problem like mynameisJEFF. (I'm using Windows and as I read here: http://mail.openjdk.java.net/pipermail/openjfx-dev/2016-June/019234.htmlit is the SPACE_BAR and not ENTER, which fires a Button in JavaFX) I didn't want to add a listener to every Button, so I registered a Listener to the root node and asked the scene, which node is focused to fire that one. Here is my code (it is xtend, but I think it very easy to understand):
我遇到了与 mynameisJEFF 相同的问题。（我正在使用 Windows，正如我在此处阅读的：http: //mail.openjdk.java.net/pipermail/openjfx-dev/2016-June/019234.html 它是 SPACE_BAR 而不是 ENTER，它会在JavaFX）我不想为每个按钮添加一个监听器，所以我在根节点注册了一个监听器并询问场景，哪个节点专注于触发那个。这是我的代码（它是 xtend，但我认为它很容易理解）：
override start(Stage primaryStage) throws Exception {
val root = FXTable.createRoot
val mainScene = new Scene(root)
root.addEventHandler(KeyEvent.KEY_RELEASED, [event|
if(event.code === KeyCode.ENTER){
switch(focusedNode : mainScene.focusOwnerProperty.get){
Button:{
focusedNode.fire
event.consume
}
default:{
}
}
}
])
primaryStage.scene = mainScene
primaryStage.show
primaryStage.maximized = true
}
回答by Abdul.Moqueet
You can dynamically change the default button property of the currently focused button by using binding
您可以使用绑定动态更改当前聚焦按钮的默认按钮属性
btn.defaultButtonProperty().bind(btn.focusedProperty());
回答by ARiyou Jahan
There is a much more simple a standard way to do that using setOnKeyPressed
使用setOnKeyPressed有一种更简单的标准方法来做到这一点
okayButton.setOnKeyPressed(event -> {
if (event.getCode().equals(KeyCode.ENTER)) {
okayButton.fire();
}
}
);
And don't forget that you should define SetOnAction too, other way it's work but it's doing nothing.
并且不要忘记您也应该定义 SetOnAction ，否则它可以工作但它什么也不做。
okayButton.setOnAction(event -> {
// Do what ever you want to your button do. Like :
System.Out.Print("Okay Button Fired (Clicked or Pressed");
}
);
