string 使用awk在字符串中查找字符串
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find a string in a string using awk
提问by AWE
here is column 6 in a file:
这是文件中的第 6 列：
ttttttttttt
tttttttttt
ttttttttt
tttttttattt
tttttttttt
ttttttttttt
how can I use awk to print out lines that include "a"
如何使用 awk 打印出包含“a”的行
采纳答案by Kevin
If you only want to search the sixth column, use:
如果只想搜索第六列，请使用：
awk ' ~ /a/' file
If you want the whole line, any of these should work:
如果你想要整条线，这些都应该有效：
awk /a/ file
grep a file
sed '/^[^a]*$/d' file
回答by jaypal singh
If you wish to print only those lines in which 6th column contains athen this would work -
如果您只想打印第 6 列包含的那些行，a那么这将起作用-
awk '$6~/a/' file
awk '$6~/a/' file
回答by Henry Barber
if it is an exact match (which yours is not) you're looking for:
如果它是一个完全匹配（你的不是）你正在寻找：
$6 == "a"
$6 == "a"
http://www.pement.org/awk/awk1line.txtis an excellent resource
http://www.pement.org/awk/awk1line.txt是一个很好的资源
awk can also tell you where the pattern is in the column:
awk 还可以告诉您模式在列中的位置：
awk '{++line_num}{ if ( match(,"a")) { print "found a at position",RSTART, " line " ,line_num} }' file
though this example will only show the first "a" in column 6; a for loop would be needed to show all instances (I think)
虽然这个例子只会显示第 6 列中的第一个“a”；需要一个 for 循环来显示所有实例（我认为）
回答by souser
You could try
你可以试试
gawk '{ if ( ~ /a/ ) { print } }' filename
