bash Linux：在案例中调用函数
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Linux: Calling a function within a case
提问by Seatter
I am trying to set up a menu system where on selection it runs a function. In my case is runs the 'testfunc' function. However is it fails giving the error; testfunc: command not found.
我正在尝试建立一个菜单系统，在其中选择它运行一个功能。在我的情况下是运行'testfunc'函数。但是它没有给出错误；testfunc：找不到命令。
My case statement looks like this;
我的案例陈述看起来像这样；
case "$mainMenuInput" in
1)testfunc ;;
esac
function testfunc{
echo "This is a test"
}
Thanks in advance.
提前致谢。
回答by Jan Hudec
Shell scripts are executed statement at a time. The function is only known from the point you define it. You have to move it before the call.
Shell 脚本一次执行一条语句。该函数仅在您定义它时才知道。你必须在通话前移动它。
