php 发布具有相同名称属性的表单字段
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POSTing Form Fields with same Name Attribute
提问by danwellman
If you have a form containing text inputs with duplicate nameattributes, and the form is posted, will you still be able to obtain the values of all fields from the $_POSTarray in PHP?
如果您有一个包含具有重复name属性的文本输入的表单，并且该表单已发布，您是否仍然能够$_POST在 PHP 中从数组中获取所有字段的值？
回答by Gordon
No. Only the last input element will be available.
否。只有最后一个输入元素可用。
If you want multiple inputs with the same name use name="foo[]"for the input name attribute. $_POSTwill then contain an array for foo with all values from the input elements.
如果您想要多个具有相同名称的输入，请使用name="foo[]"输入名称属性。$_POST然后将包含一个 foo 数组，其中包含来自输入元素的所有值。
<form method="post">
<input name="a[]" value="foo"/>
<input name="a[]" value="bar"/>
<input name="a[]" value="baz"/>
<input type="submit" />
</form>
See the HTML reference at Sitepoint.
请参阅Sitepoint 上的HTML 参考。
The reason why $_POSTwill only contain the last value if you don't use []is because PHP will basically just explode and foreach over the raw query string to populate $_POST. When it encounters a name/value pair that already exists, it will overwrite the previous one.
$_POST如果您不使用，则只包含最后一个值的原因[]是因为 PHP 基本上只会爆炸并在原始查询字符串上 foreach 来填充$_POST。当它遇到一个已经存在的名称/值对时，它会覆盖前一个。
However, you can still access the raw query string like this:
但是，您仍然可以像这样访问原始查询字符串：
$rawQueryString = file_get_contents('php://input'))
Assuming you have a form like this:
假设你有一个这样的表格：
<form method="post">
<input type="hidden" name="a" value="foo"/>
<input type="hidden" name="a" value="bar"/>
<input type="hidden" name="a" value="baz"/>
<input type="submit" />
</form>
the $rawQueryStringwill then contain a=foo&a=bar&a=baz.
rawQueryString然后$将包含a=foo&a=bar&a=baz.
You can then use your own logic to parse this into an array. A naive approach would be
然后，您可以使用自己的逻辑将其解析为数组。一种天真的方法是
$post = array();
foreach (explode('&', file_get_contents('php://input')) as $keyValuePair) {
list($key, $value) = explode('=', $keyValuePair);
$post[$key][] = $value;
}
which would then give you an array of arrays for each name in the query string.
然后将为查询字符串中的每个名称提供一个数组数组。
回答by Daniel Mihai
Instead of name="nfo[val]"just use name="nfo[val][]"and in PHP you can use a foreach()
而不是name="nfo[val]"仅仅使用name="nfo[val][]"和在 PHP 中，您可以使用foreach()
HTML code:
HTML代码：
<form method="post">
<input name="nfo[val][]" value="val1"/>
<input name="nfo[val][]" value="val2"/>
<input name="nfo[val][]" value="val3"/>
<input type="submit" />
</form>
PHP code:
PHP代码：
$output='';
foreach ($nfo['val'] as $key=>$val) {
$output.= $val.", ";
}
$outputwill be: val1, val2, val3
$output将会： val1, val2, val3
Hope this helps!
希望这可以帮助！
回答by streetparade
You have to create an array of them:
with name=inputname[]and get with post,request or get
您必须创建一个数组：withname=inputname[]和 get with post、request 或 get
$inputs = $_POST['inputname'];
print_r($inputs);
回答by jpabluz
Only if the name are array-typed names[]in that case you will be getting an array as the variable in the $_POST variable.
只有names[]在这种情况下名称是数组类型时，您才会在 $_POST 变量中获得一个数组作为变量。
