ruby 如何遍历哈希数组并返回单个字符串中的值？
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How do I iterate over an array of hashes and return the values in a single string?
提问by splatoperator
Sorry if this obvious, I'm just not getting it. If I have an array of hashes like:
对不起，如果这很明显，我只是不明白。如果我有一个哈希数组，例如：
people = [{:name => "Bob", :occupation=> "Builder"}, {:name => "Jim", :occupation =>
"Coder"}]
And I want to iterate over the array and output strings like: "Bob: Builder". How would I do it? I understand how to iterate, but I'm still a little lost. Right now, I have:
我想遍历数组并输出字符串，例如：“Bob：Builder”。我该怎么做？我知道如何迭代，但我还是有点迷茫。现在，我有：
people.each do |person|
person.each do |k,v|
puts "#{v}"
end
end
My problem is that I don't understand how to return both values, only each value separately. What am I missing?
我的问题是我不明白如何返回两个值，只分别返回每个值。我错过了什么？
Thank you for your help.
感谢您的帮助。
回答by Richard Cook
Here you go:
干得好：
puts people.collect { |p| "#{p[:name]}: #{p[:occupation]}" }
Or:
或者：
people.each do |person|
puts "#{person[:name]}: #{person[:occupation]}"
end
In answer to the more general query about accessing the values in elements within the array, you need to know that peopleis an array of hashes. Hashes have a keysmethod and valuesmethod which return the keys and values respectively. With this in mind, a more general solution might look something like:
为了回答有关访问数组中元素值的更一般查询，您需要知道这people是一个散列数组。哈希有一个keys方法和values方法，分别返回键和值。考虑到这一点，更通用的解决方案可能如下所示：
people.each do |person|
puts person.values.join(': ')
end
回答by Varus Septimus
Will work too:
也将工作：
people.each do |person|
person.each do |key,value|
print key == :name ? "#{value} : " : "#{value}\n"
end
end
Output:
输出：
Bob : Builder
Jim : Coder
