在 Python 中获取硬盘大小
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Get hard disk size in Python
提问by Nisba
I am trying to get the hard drive size and free space using Python (I am using Python 2.7 with macOS).
我正在尝试使用 Python 获取硬盘驱动器大小和可用空间（我在 macOS 上使用 Python 2.7）。
I am trying with os.statvfs('/'), especially with the following code.
Is it correct what I am doing? Which definition of the variable gigashall I use?
我正在尝试os.statvfs('/')，尤其是使用以下代码。我在做什么是正确的吗？giga我应该使用变量的哪个定义？
import os
def get_machine_storage():
result=os.statvfs('/')
block_size=result.f_frsize
total_blocks=result.f_blocks
free_blocks=result.f_bfree
# giga=1024*1024*1024
giga=1000*1000*1000
total_size=total_blocks*block_size/giga
free_size=free_blocks*block_size/giga
print('total_size = %s' % total_size)
print('free_size = %s' % free_size)
get_machine_storage()
EDIT:
statvfsis deprecated in Python 3, do you know any alternative?
编辑：
statvfs在 Python 3 中已弃用，您知道有其他选择吗？
回答by Vasilis G.
For Python 2 till Python 3.3
对于 Python 2 到 Python 3.3
Notice: As a few people mentioned in the comment section, this solution will work for Python 3.3and above. For Python 2.7it is best to use the psutillibrary, which has a disk_usagefunction, containing information about total, usedand freedisk space:
注意：正如评论部分中提到的一些人，此解决方案适用于Python 3.3及更高版本。对于Python 2.7，最好使用该psutil库，它有一个disk_usage函数，包含有关总磁盘空间、已用磁盘空间和可用磁盘空间的信息：
import psutil
hdd = psutil.disk_usage('/')
print ("Total: %d GiB" % hdd.total / (2**30))
print ("Used: %d GiB" % hdd.used / (2**30))
print ("Free: %d GiB" % hdd.free / (2**30))
Python 3.3 and above:
Python 3.3 及更高版本：
For Python 3.3 and above, you can use the shutilmodule, which has a disk_usagefunction, returning a named tuple with the amounts of total, used and free space in your hard drive.
对于 Python 3.3 及更高版本，您可以使用该shutil模块，该模块具有一个disk_usage函数，返回一个命名元组，其中包含硬盘驱动器中的总空间、已用空间和可用空间。
You can call the function as below and get all information about your disk's space:
您可以按如下方式调用该函数并获取有关磁盘空间的所有信息：
import shutil
total, used, free = shutil.disk_usage("/")
print("Total: %d GiB" % (total // (2**30)))
print("Used: %d GiB" % (used // (2**30)))
print("Free: %d GiB" % (free // (2**30)))
Output:
输出：
Total: 931 GiB
Used: 29 GiB
Free: 902 GiB
回答by Fausto Branco
https://pypi.python.org/pypi/psutil
https://pypi.python.org/pypi/psutil
import psutil
obj_Disk = psutil.disk_usage('/')
print (obj_Disk.total / (1024.0 ** 3))
print (obj_Disk.used / (1024.0 ** 3))
print (obj_Disk.free / (1024.0 ** 3))
print (obj_Disk.percent)
回答by lenik
The code is about right, but you're using wrong fields, which may give you the wrong results on a different system. The correct way would be:
代码大致正确，但是您使用了错误的字段，这可能会在不同的系统上给您错误的结果。正确的方法是：
>>> os.system('df -k /')
Filesystem 1K-blocks Used Available Use% Mounted on
/dev/root 14846608 3247272 10945876 23% /
>>> disk = os.statvfs('/')
>>> (disk.f_bavail * disk.f_frsize) / 1024
10945876L
回答by Hadus
Printing out the type can help, when you don't know how to handle a function's result.
当您不知道如何处理函数的结果时，打印出类型会有所帮助。
print type(os.statvfs('/'))returns <type 'posix.statvfs_result'>
print type(os.statvfs('/'))返回 <type 'posix.statvfs_result'>
That means it isn't a built in class instance like a string or int..
这意味着它不是像 string 或 int 那样的内置类实例。
You can check what you can do with that instance with dir(instance)
你可以检查你可以用这个实例做什么 dir(instance)
print dir(os.statvfs('/'))prints all of it's the properties, functions, variables...
print dir(os.statvfs('/'))打印所有的属性、函数、变量......
['__add__', '__class__', '__contains__', '__delattr__', '__doc__',
'__eq__', '__format__', '__ge__', '__getattribute__', '__getitem__',
'__getslice__', '__gt__', '__hash__', '__init__', '__le__', '__len__',
'__lt__', '__mul__', '__ne__', '__new__', '__reduce__',
'__reduce_ex__', '__repr__', '__rmul__', '__setattr__', '__sizeof__',
'__str__', '__subclasshook__', 'f_bavail', 'f_bfree', 'f_blocks',
'f_bsize', 'f_favail', 'f_ffree', 'f_files', 'f_flag', 'f_frsize',
'f_namemax', 'n_fields', 'n_sequence_fields', 'n_unnamed_fields']
By accessing one of the variables, like os.statvfs('/').f_ffreeyou can extract an integer.
通过访问其中一个变量，就像os.statvfs('/').f_ffree您可以提取一个整数一样。
Double check with print type(os.statvfs('/').f_ffree),
it does print <type 'int'>.
仔细检查print type(os.statvfs('/').f_ffree)，它确实会打印<type 'int'>。
