Linux 如何反转grep表达式
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How to invert a grep expression
提问by sMaN
The following grep expression successfully lists all the .exe and .html files in the current directory and sub directories.
以下 grep 表达式成功列出了当前目录和子目录中的所有 .exe 和 .html 文件。
ls -R |grep -E .*[\.exe]$\|.*[\.html]$
How do I invert this result to list those that aren't a .html or .exe instead. (That is, !=.)
我如何反转这个结果以列出那些不是 .html 或 .exe 的结果。（也就是说，!=。）
采纳答案by Eric Fortis
Use command-line option -vor --invert-match,
使用命令行选项-v或--invert-match，
ls -R |grep -v -E .*[\.exe]$\|.*[\.html]$
回答by darioo
回答by Rob Sobers
Add the -voption to your grepcommand to invert the results.
将-v选项添加到您的grep命令以反转结果。
回答by Anja Ishmukhametova
grep "subscription" | grep -v "spec"
回答by jmd_dk
As stated multiple times, inversion is achieved by the -voption to grep. Let me add the (hopefully amusing) note that you could have figured this out yourself by grepping through the grephelp text:
正如多次所述，反转是通过-v选项实现的grep。让我添加（希望是有趣的）注释，您可以通过搜索grep帮助文本来自己解决这个问题：
grep --help | grep invert
-v, --invert-match select non-matching lines
-v, --invert-match 选择不匹配的行
