java 将 Jersey 项目（Rest web 服务）运行到 tomcat
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Running Jersey project (Rest web service) to tomcat
提问by Dany
I'm try to follow this guide: tutorialbut when I execute on the web browser it returns an error:
我正在尝试遵循本指南：教程，但是当我在网络浏览器上执行时，它返回一个错误：
HTTP Status 404 - /
type Status report
message /
description The requested resource (/rest.api/rest/hello) is not available.
I have installed tomcat7 in /usr/local on my mac and ran it with startup.sh on the terminal. This is my web.xml and Hello.java
我已经在我的 mac 上的 /usr/local 中安装了 tomcat7，并在终端上使用 startup.sh 运行它。这是我的 web.xml 和 Hello.java
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
<display-name>HelloRest</display-name>
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>rest.api</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>Jersey REST Service</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
package rest.api;
import javax.ws.rs.GET;
import javax.ws.rs.Path;
import javax.ws.rs.Produces;
import javax.ws.rs.core.MediaType;
// POJO, no interface no extends
// The class registers its methods for the HTTP GET request using the @GET annotation.
// Using the @Produces annotation, it defines that it can deliver several MIME types,
// text, XML and HTML.
// The browser requests per default the HTML MIME type.
//Sets the path to base URL + /hello
@Path("/hello")
public class Hello {
// This method is called if TEXT_PLAIN is request
@GET
@Produces(MediaType.TEXT_PLAIN)
public String sayPlainTextHello() {
return "Hello Jersey";
}
// This method is called if XML is request
@GET
@Produces(MediaType.TEXT_XML)
public String sayXMLHello() {
return "<?xml version=\"1.0\"?>" + "<hello> Hello Jersey" + "</hello>";
}
// This method is called if HTML is request
@GET
@Produces(MediaType.TEXT_HTML)
public String sayHtmlHello() {
return "<html> " + "<title>" + "Hello Jersey" + "</title>"
+ "<body><h1>" + "Hello Jersey" + "</body></h1>" + "</html> ";
}
}
This is my configuration project:
这是我的配置项目：
Any suggest?
有什么建议吗？
采纳答案by Yogesh Prajapati
Just use following configuration in web.xml
只需在web.xml 中使用以下配置
<servlet>
<servlet-name>ServletAdaptor</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>ServletAdaptor</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
hope this will help you.
希望这会帮助你。
回答by Pradip Bhatt
Try this one.
试试这个。
<servlet>
<servlet-name>jersey-serlvet</servlet-name>
<servlet-class>com.sun.jersey.spi.container.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>com.sun.jersey.config.property.packages</param-name>
<param-value>Your Service Package Name</param-value>
</init-param>
<init-param>
<param-name>com.sun.jersey.api.json.POJOMappingFeature</param-name>
<param-value>true</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
<servlet-mapping>
<servlet-name>jersey-serlvet</servlet-name>
<url-pattern>/rest/*</url-pattern>
</servlet-mapping>
Visit this one : Jersey RESTful
访问这个：Jersey RESTful
回答by Franklin M Gauer III
In more recent versions of Jersey the servlet-class and init-param change. Try the following:
在最新版本的 Jersey 中，servlet-class 和 init-param 发生了变化。请尝试以下操作：
<servlet>
<servlet-name>Jersey REST Service</servlet-name>
<servlet-class>org.glassfish.jersey.servlet.ServletContainer</servlet-class>
<init-param>
<param-name>jersey.config.server.provider.packages</param-name>
<param-value>Your Service Package Name</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
This worked for me using Jersey version: 2.5.1.
这对我使用 Jersey 版本有效：2.5.1。
回答by Prashant Yewalekar
<servlet-name> jersey-serlvet </servlet-name>
<servlet-class> com.sun.jersey.spi.container.servlet.ServletContainer </servlet-class>
<init-param>
<param-name> com.sun.jersey.config.property.packages </param-name>
<param-value> rest.api </param-value>
</init-param>
<init-param>
<param-name> com.sun.jersey.api.json.POJOMappingFeature </param-name>
<param-value> true </param-value>
</init-param>
<load-on-startup>1</load-on-startup>
<servlet-name> jersey-serlvet </servlet-name>
<url-pattern> /rest/* </url-pattern>
