如何在 bash for 循环中内联字符串数组？
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How do I inline an array of strings in a bash for loop?
提问by expert
How do I inline an array of strings in a bash for loop ? This works:
如何在 bash for 循环中内联字符串数组？这有效：
array=(one two)
for i in ${array[*]};do echo $i; done
But I'd like to eliminate the extra local variable. I've tried many variations that seem reasonable, for example:
但我想消除额外的局部变量。我尝试了许多看起来合理的变体，例如：
for i in ${("one" "two")[*]};do echo $i; done
or
或者
for i in ${"one" "two"};do echo $i; done
In each case, it treats oneand twoas commands :(
在每种情况下，它都将one和two视为命令:(
回答by Alija Bevrnja
Did you try with:
您是否尝试过：
for i in "one" "two"; do echo "$i"; done
for i in "one" "two"; do echo "$i"; done
回答by J.O.L.
for i in {one,two}; do echo "$i"; done
