尝试读取 xsl 中的 xml 元素值
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Trying to read xml element value in xsl
提问by user1818397
I am new to XSL. I am trying to read values of XML elements using a XSL file. My XML file is like:
我是XSL 的新手。我正在尝试使用 XSL 文件读取 XML 元素的值。我的 XML 文件是这样的：
<PersonList>
<Person>
<Name>person1</Name>
<Age>21</Age>
</Person>
<Person>
<Name>person2</Name>
<Age>21</Age>
</Person>
</PersonList>
My XSL file is like:
我的 XSL 文件是这样的：
<xsl:stylesheet version="1.0" xmlns=...>
<xsl:output method="xml" indent="yes" encoding="utf-8" omit-xml declaration="no" />
<xsl template match="/">
<PersonList>
<xsl:for-each select="PersonList/Person">
<Person>
<xsl:for-each select="*">
<xsl:variable name="elementName">
<xsl:value-of select="name(.)" />
</xsl:variable>
<xsl:variable name="elementValue">
???
</xsl:variable>
</xsl:for-each>
</Person>
</xsl:for-each>
</PersonList>
</xsl:template>
</xsl:stylesheet>
How should I replace ???to get the value of the element stored in the elementNamevariable. I tried the following three lines separately:
我应该如何替换???以获取存储在elementName变量中的元素的值。我分别尝试了以下三行：
<xsl:value-of select="value(.)" />
<xsl:value-of select="value($elementName)" />
<xsl:value-of select="$elementName" />
but no luck. Please help!
但没有运气。请帮忙！
回答by Francis Avila
Your ??????????????????can be <xsl:value-of select="."/>(i.e. the string-value of the context element.) It has no connection to $elementName.
您??????????????????可以是<xsl:value-of select="."/>（即上下文元素的字符串值。）它与$elementName.
You can do this much more succinctly like this:
你可以像这样更简洁地做到这一点：
<xsl:for-each select="*">
<xsl:variable name="elementName" select="name()"/>
<xsl:variable name="elementValue" select="string(.)"/>
</xsl:for-each>
However your template is really strange. You're collecting these variables but you're not doing anything with them--they won't appear in the output. What output are you trying to get?
但是你的模板真的很奇怪。您正在收集这些变量，但您没有对它们做任何事情——它们不会出现在输出中。你想得到什么输出？
Use of for-eachis generally a code smell. In almost all cases you're better off with multiple templates:
使用的for-each一般是代码异味。在几乎所有情况下，您最好使用多个模板：
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes" encoding="utf-8" omit-xml-declaration="no" />
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
<xsl:template match="Person/*">
<xsl:variable name="elementName" select="name()"/>
<xsl:variable name="elementValue" select="string(.)"/>
</xsl:template>
</xsl:stylesheet>
This pattern where you copy almost everything and change just a little bit of the xml is very common and very powerful and you should learn how to use it.
这种复制几乎所有内容并仅更改一点点 xml 的模式非常常见且非常强大，您应该学习如何使用它。
回答by Tim C
Well, if you really wanted to get the value of an element whose name is held in a variable, in your case you would do it like this
好吧，如果您真的想获取名称保存在变量中的元素的值，那么在您的情况下，您可以这样做
<xsl:variable name="elementValue">
<xsl:value-of select="../*[name()=$elementName]" />
</xsl:variable>
But, this is greatly overcomplicated matters. You are in a xsl:for-eachloop, iterating over the child elements of a Person. Therefore, because you are already positioned on the element for which you want the value, you can just do this and forget about the elementNamevariable.
但是，这是非常复杂的事情。您在xsl:for-each循环中，迭代Person的子元素。因此，因为您已经定位在您想要其值的元素上，所以您可以只执行此操作而忘记elementName变量。
<xsl:variable name="elementValue">
<xsl:value-of select="."/>
</xsl:variable>
In fact, in you could simplify your loops to just this
实际上，您可以将循环简化为这样
<xsl:for-each select="PersonList/Person">
<Person>
<xsl:for-each select="*">
<xsl:value-of select="." />
</xsl:for-each>
</Person>
</xsl:for-each>
