在 2 周内在 php 中获取日期
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Get date in php in 2 weeks
提问by anonymous123
$addhr = time() + (1 * 13 * 60 * 60);
$curDateTimeMil= date("Y-m-d G:i:s",$addhr);
echo $curDateTimeMil;
This will echo 2010-08-27 16:21:31
.
这将回声2010-08-27 16:21:31
。
How can I get the date after 2 weeks? (sept 10)
我怎样才能在 2 周后获得日期?(9 月 10 日)
回答by jensgram
$dateInTwoWeeks = strtotime('+2 weeks');
See strtotime()
.
Update #1: Yes, this is the lazy way to do it. However, I do believe that the possiblenegative performance impact is countered by the positive effect on readability / understanding of the code. Should performance be an issue, one could switch to native (integer-based) time manipulation (and add comments).
更新 #1:是的,这是一种懒惰的方法。但是,我确实相信可能的负面性能影响会被对代码可读性/理解的积极影响所抵消。如果性能是一个问题,可以切换到本机(基于整数)时间操作(并添加注释)。
Update #2: The optional second argument is the reference date. E.g.:
更新 #2:可选的第二个参数是参考日期。例如:
strtotime('+2 weeks', mktime(0, 0, 0, 2, 8, 1984)); // 8th Feb. 1984 + 2 weeks
回答by shamittomar
You can specify the starting time (from where to calculate) using mktime()
.
您可以使用 指定开始时间(从哪里计算)mktime()
。
Example: Two week after September 10, 2010 (i.e. +14 days):
示例:2010 年 9 月 10 日之后的两周(即 +14 天):
$date = date("Y-m-d", mktime(0, 0, 0, 9, 10 + 14, 2010);
To get just the DATE (not time) of two weeks later (+14 days) from today:
从今天起仅获取两周后(+14 天)的 DATE(而非时间):
$date = date("Y-m-d", mktime(0, 0, 0, date("m"), date("d")+14, date("Y")));
And this gives with TIME of two weeks later (+14 days) from now:
这是从现在起两周后(+14 天)的 TIME:
$date = date("Y-m-d G:i:s", mktime(date("G"), date("i"), date("s"), date("m"), date("d")+14, date("Y")));
回答by Gumbo
You could simply add the number seconds of two weeks:
您可以简单地添加两周的秒数:
2 weeks = 2 · 7 days = 14 days
= 14 · 24 hours = 336 hours
= 336 · 60 minutes = 20160 minutes
= 20160 · 60 seconds = 1209600 seconds
So:
所以:
$curDateTimeMil += 1209600;
// or
$curDateTimeMil += 2 * 7 * 24 * 60 * 60;