Java 如何使用正则表达式替换括号中的字符串？
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How can I replace a string in parentheses using a regex?
提问by Lily
I have a string:
我有一个字符串：
HLN (Formerly Headline News)
I want to remove everything inside the parens and the parens themselves, leaving only:
我想删除括号内的所有内容和括号本身，只留下：
HLN
I've tried to do this with a regex, but my difficulty is with this pattern:
我试图用正则表达式来做到这一点，但我的困难在于这种模式：
"(.+?)"
When I use it, it always gives me a PatternSyntaxException. How can I fix my regex?
当我使用它时，它总是给我一个PatternSyntaxException. 如何修复我的正则表达式？
采纳答案by jjnguy
Because parentheses are special characters in regexps you need to escape them to match them explicitly.
因为括号是正则表达式中的特殊字符，所以您需要对它们进行转义以明确匹配它们。
For example:
例如：
"\(.+?\)"
回答by iammichael
You could use the following regular expression to find parentheticals:
您可以使用以下正则表达式来查找括号：
\([^)]*\)
the \(matches on a left parenthesis, the [^)]*matches any number of characters other than the right parenthesis, and the \)matches on a right parenthesis.
在\(上一个左括号匹配，在[^)]*匹配任何数量比右括号其他字符，而\)上一个右括号匹配。
If you're including this in a java string, you must escape the \characters like the following:
如果您将其包含在 java 字符串中，则必须转义如下\字符：
String regex = "\([^)]*\)";
回答by Greg Mattes
String foo = "bar (baz)";
String boz = foo.replaceAll("\(.+\)", ""); // or replaceFirst
bozis now "bar "
boz就是现在 "bar "
回答by Andreas Panagiotidis
String foo = "(x)()foo(x)()";
String cleanFoo = foo.replaceAll("\([^\(]*\)", "");
// cleanFoo value will be "foo"
The above removes empty and non-empty parenthesis from either side of the string.
以上删除了字符串两侧的空括号和非空括号。
plain regex:
普通正则表达式：
\([^\(]*\)
You can test here: http://www.regexplanet.com/simple/index.html
你可以在这里测试：http: //www.regexplanet.com/simple/index.html
My code is based on previous answers
我的代码基于以前的答案
