Java 不支持的字段：格式化即时到日期 ISO 时的年份
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时间：2020-08-11 22:31:21 来源:igfitidea点击:
Unsupported field: Year when formatting an instant to Date ISO
提问by Eric Reboisson
I am trying to format an Instant to a ldap date ISO8601 but it fails at f.format(Instant.now()); :
我正在尝试将 Instant 格式化为 ldap 日期 ISO8601，但它在 f.format(Instant.now()); 处失败；：
String input = "20161012235959.0Z";
DateTimeFormatter f = DateTimeFormatter.ofPattern ( "uuuuMMddHHmmss[,S][.S]X" );
OffsetDateTime odt = OffsetDateTime.parse ( input , f );
Instant instant = odt.toInstant ();
f.format(Instant.now());
And the error is :
错误是：
java.time.temporal.UnsupportedTemporalTypeException: Unsupported field: Year
at java.time.Instant.getLong(Instant.java:603)
at java.time.format.DateTimePrintContext.getValue(DateTimePrintContext.java:298)
at java.time.format.DateTimeFormatterBuilder$NumberPrinterParser.format(DateTimeFormatterBuilder.java:2540)
at java.time.format.DateTimeFormatterBuilder$CompositePrinterParser.format(DateTimeFormatterBuilder.java:2179)
at java.time.format.DateTimeFormatter.formatTo(DateTimeFormatter.java:1746)
at java.time.format.DateTimeFormatter.format(DateTimeFormatter.java:1720)
...
...
采纳答案by andolsi zied
To format an Instant a time-zone is required.
要格式化 Instant 需要时区。
String input = "20161012235959.0Z";
DateTimeFormatter f = DateTimeFormatter
.ofPattern ( "uuuuMMddHHmmss.SX" )
.withLocale( Locale.FRANCE )
.withZone( ZoneId.of("UTC"));
OffsetDateTime odt = OffsetDateTime.parse ( input , f );
Instant instant = odt.toInstant ();
System.out.println(input);
System.out.print(f.format(instant));
