java 方法不适用于参数

Method not applicable for arguments

提问by Larry Gyamfi

I'm trying to create a tester class, but in doing so I have gotten an error which states:

我正在尝试创建一个测试员类，但这样做时我收到了一个错误，指出：

1 error found:

Error: The method printData(double, double) in the type PayCalculator is not
    applicable for the arguments ()

How do I fix it? This my tester code

我如何解决它？这是我的测试员代码

PayCalculator p1 = new PayCalculator();
    p1.setHourlyRate(8.25);
    p1.setHoursWorked(45.0);    
    p1.printData();

my main code

我的主要代码

{
  private double hourlyRate;
  private double hoursWorked;


  public PayCalculator()
  {
    hourlyRate = 0.0;
    hoursWorked = 0.0;
  }

  /**
   * Two parameter constructor
   * Add hourlyRate and hoursWorked
   * @param the hourly rate
   * @param the hours worked
   */
  public PayCalculator(double aHourlyRate, double aHoursWorked)
  {
    hourlyRate = aHourlyRate;
    hoursWorked = aHoursWorked;
  }

  /**
   * sets the hourly rate
   * @return hourlyRate
   */ 
  public void setHourlyRate(double aHourlyRate)
  {
    hourlyRate = aHourlyRate;
  }

  /**
   * gets the hourly rate
   * @param hourlyRate
   */
  public double getHourlyRate()
  {
    return hourlyRate;
  }

  /**
   * sets the hours worked
   * @return hoursWorked
   */ 
  public void setHoursWorked(double aHoursWorked)
  {
    hoursWorked = aHoursWorked;
  }

  /**
   * gets the hours worked
   * @param hours worked
   */
  public double getHoursWorked()
  {
    return hoursWorked;
  }



  public boolean workedOvertime()
  {
    if (hoursWorked > 40)
    {
      return true;
    }
    else 
    {
      return false;
    }
  }

  public double numHoursOvertime()
  {
    if (hoursWorked > 40)
    {
      return hoursWorked - 40;
    }
    else 
    {
      return 0;
    }
  }

  public double calculateGrossPay()
  {
    if (hourlyRate  <= 10.25)
    {
      if (hourlyRate <= 40)
        return hourlyRate * hoursWorked;
    }
    else 
    {  
      double grossPay = ((40 * hourlyRate) + ((hourlyRate * 2) * hoursWorked - 40));
      return grossPay;
    }

    if (hoursWorked <= 60)
    {
      return hourlyRate * hoursWorked;
    }
    else
    {
      return 60 * hourlyRate;
    }
  }

  public double determineTaxRate(double grossPay)
  {
    if (grossPay >= 800)
    {
      double tax = 0;
      tax = grossPay * 0.37;
      return tax;
    }
    else if ( grossPay >= 400)
    {
      double tax = 0;
      tax = grossPay * 0.22;
      return tax;
    }
    else
    {
      double tax = 0;
      tax = grossPay * 0.12;
      return tax;
    }
  }

  public double calculateNetPay(double grossPay, double tax)
  {
    double calculateNetPay = grossPay - tax;
    return calculateNetPay;
  }

  public void printData(double grossPay, double tax)
  {
    System.out.println("Hours Worked: " + hoursWorked);
    System.out.println("Hourly rate: " + hourlyRate);
    System.out.println("Number of hours of overtime worked: " + numHoursOvertime());
    System.out.println("Worked overtime? " + workedOvertime());
    System.out.println("Gross pay: " + calculateGrossPay());
    System.out.println("Tax Rate: " + determineTaxRate(grossPay));
    System.out.println("Net Pay: " + calculateNetPay(grossPay, tax));
  }
}

回答by Jon Skeet

Well yes. Here's the method declaration:

嗯，是。这是方法声明：

public void printData(double grossPay, double tax)

And here's how you're trying to call it:

这是您尝试调用它的方式：

p1.printData();

What values do you expect to be used for grossPayand tax?

您希望将哪些值用于grossPay和tax？

To be honest it seems odd that you should have to pass in grossPayhaving already specified the hours worked and hourly rate, but that's a different matter. The most immediate problem is that you're not providing the arguments your method requires.

老实说，您必须grossPay已经指定工作时间和小时费率，这似乎很奇怪，但这是另一回事。最直接的问题是您没有提供方法所需的参数。

回答by Abubakkar

Your method expects two values grossPayand tax:

您的方法需要两个值grossPay和tax：

public void printData(double grossPay, double tax)

But you are not providing grossPayand taxto it when calling it :

但是在调用它时你没有提供 grossPay和tax给它：

p1.printData();

Include the value of grossPayand taxwhen calling your method and it will work fine like :

包括价值 grossPay和tax调用您的方法时，它会像罚款：

p1.printData(123.00,2.5);

回答by navyad

Definition of your method is:

您的方法的定义是：

public void printData(double grossPay, double tax)

It expects call with two double arguments whereas you are calling with no argument:

它期望使用两个双参数调用，而您不带参数调用：

p1.printData();

Pass double arguments to printData(44.85d, 77.56d)

将双参数传递给 printData(44.85d, 77.56d)