将数组拆分为 2 个数组 C#
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Splitting an array into 2 arrays C#
提问by matthewr
Edit: I have tried the Take/Skip method but I get the following error:
编辑：我尝试了 Take/Skip 方法，但出现以下错误：
Cannot implicitly convert type 'System.Collections.Generic.IEnumerable<string>' to
'string[]'. An explicit conversion exists (are you missing a cast?)
I do not know what I am doing wrong because I copied Saeed's code.
我不知道我做错了什么，因为我复制了 Saeed 的代码。
I have a string array (containing anywhere from 20 to 300 items) and I want to split it into 2 separate arrays, from the middle of the first one.
我有一个字符串数组（包含 20 到 300 个项目），我想将它从第一个数组的中间拆分为 2 个单独的数组。
I know how I can do this using a for loop but I would like to know if there was a faster/better way of doing it. I also need to be able to correctly split an array even if it has an odd number of items, eg:
我知道如何使用 for 循环来做到这一点，但我想知道是否有更快/更好的方法来做到这一点。我还需要能够正确拆分数组，即使它有奇数个项目，例如：
string[] words = {"apple", "orange", "banana", "pear", "lemon"};
string[] firstarray, secondarray;
SplitArray(words, out firstarray, out secondarray); // Or some other function
// firstarray has the first 3 of the items from words, 'apple', 'orange' and 'banana'
// secondarray has the other 2, 'pear' and 'lemon'
采纳答案by Saeed Amiri
You can use linq:
您可以使用 linq：
firstArray = array.Take(array.Length / 2).ToArray();
secondArray = array.Skip(array.Length / 2).ToArray();
Why this works, despite the parity of the original array size?
尽管原始数组大小的奇偶校验，为什么这有效？
The firstArray takes array.Length / 2elements, and the second one skips the first array.Length / 2elements, it means there isn't any conflict between these two arrays. Of course if the number of elements is odd we cannot split the array into two equal size parts.
firstArray 接受array.Length / 2元素，第二个跳过第一个array.Length / 2元素，这意味着这两个数组之间没有任何冲突。当然，如果元素的数量是奇数，我们就不能将数组分成两个大小相等的部分。
If you want to have more elements in the first half (in the odd case), do this:
如果您想在前半部分（在奇数情况下）有更多元素，请执行以下操作：
firstArray = array.Take((array.Length + 1) / 2).ToArray();
secondArray = array.Skip((array.Length + 1) / 2).ToArray();
回答by Asif Mushtaq
string[] words = {"apple", "orange", "banana", "pear", "lemon"};
int mid = words.Length/2;
string[] first = words.Take(mid).ToArray();
string[] second = words.Skip(mid).ToArray();
回答by Nope
string[] words = { "apple", "orange", "banana", "pear", "lemon" };
var halfWay = words.Length/2;
var firstHalf = words.Take(halfWay);
var secondHalf = words.Skip(halfWay);
回答by Totero
A more generalized approach that will split it into as many parts as you specify:
一种更通用的方法，将其拆分为您指定的多个部分：
public static IEnumerable<IEnumerable<T>> Split<T>(this IEnumerable<T> list, int parts)
{
return list.Select((item, index) => new {index, item})
.GroupBy(x => (x.index + 1) / (list.Count()/parts) + 1)
.Select(x => x.Select(y => y.item));
}
*Edited Thanks skarmats
*编辑感谢skarmats
回答by Francesco Baruchelli
If you don't want to/can't use LINQ you can simply do:
如果您不想/不能使用 LINQ，您可以简单地执行以下操作：
string[] words = { "apple", "orange", "banana", "pear", "lemon" };
string[] firstarray, secondarray;
int mid = words.Length / 2;
firstarray = new string[mid];
secondarray = new string[words.Length - mid];
Array.Copy(words, 0, firstarray, 0, mid);
Array.Copy(words, mid, secondarray, 0, secondarray.Length);
回答by Khaled Saleh
Just in case someone wants to use a function instead:
以防万一有人想改用函数：
static void Main(string[] args)
{
string[] ar = { "apple", "orange", "banana", "pear", "lemon" };
int half = ar.Length / 2;
// Console.WriteLine(string.Join(',', Split(ar,0, half)));
Console.WriteLine(string.Join(',', Split(ar,half, ar.Length)));
Console.ReadKey();
}
public static IEnumerable<T> Split<T>(IEnumerable<T> items, int start, int end)
{
return items.Skip(start).Take(end);
}
