java 将字节数组转换为十进制
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Convert byte array to decimal
提问by Wearybands
I have a byte array and I want to do some manipulation on the basis of the data I have in this array. The content of the byte array is in hexadecimal format.
我有一个字节数组，我想根据这个数组中的数据进行一些操作。字节数组的内容为十六进制格式。
byte[] signal = message.getFieldValue( "_Decoder Message" ).data();
This gives me the byte array with the following content
这给了我包含以下内容的字节数组
[ff ff 11 ff ff 82 05 00 13 00 d7 00 fc dc 03 04 00 00 01 00 00 00 1e 00 00 00 52 00 00]
Is it possible to convert this byte array to an array which contains values in decimal ? Or if I am interested in any specific index how can I convert the value of that index to decimal ?
是否可以将此字节数组转换为包含十进制值的数组？或者，如果我对任何特定索引感兴趣，我该如何将该索引的值转换为十进制？
Let say I want to convert index 18 which in byte array is 01. I am using Java btw.
假设我想转换字节数组中的索引 18 为 01。顺便说一句，我正在使用 Java。
Thanks
谢谢
回答by stinepike
public int[] bytearray2intarray(byte[] barray)
{
int[] iarray = new int[barray.length];
int i = 0;
for (byte b : barray)
iarray[i++] = b & 0xff;
return iarray;
}
