如何在 Python 中将浮点数四舍五入到最接近的整数
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how to round a float number to the nearest integer in Python
提问by fsaizpoy
The function round(x) in Python yields floating number. Therefore, what is the most appropriate code in Python to round a float to the nearest neighbor?
Python 中的函数 round(x) 产生浮点数。因此，Python 中将浮点数舍入到最近邻的最合适的代码是什么？
回答by Simone Zandara
It seems that round already does what you want, or maybe I did not understand the question.
似乎 round 已经做了你想要的，或者也许我没有理解这个问题。
>>> round(3.2)
3
>>> round(3.8)
4
>>> a = round(3.8)
>>> type(a)
<class 'int'>
EDIT
编辑
Python3 round returns an integer, but in Python2.7 round returns a float. For Python2.7 just do:
Python3 轮返回一个整数，但在 Python2.7 轮返回一个浮点数。对于 Python2.7，只需执行以下操作：
int(round(x))
