如何在 Laravel 中在没有请求的情况下进行验证
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How to validate without request in Laravel
提问by user3743266
I need to validate an array but without a request. In laravel docs validation is described like this:
我需要验证一个数组但没有请求。在 laravel docs 验证是这样描述的：
$validator = Validator::make($request->all(), [
'title' => 'required|unique:posts|max:255',
'body' => 'required',
]);
But I can't use $request because the data comes from an external api and the validation is not inside a controller. How can I validate this array? For example:
但是我不能使用 $request 因为数据来自外部 api 并且验证不在控制器内部。我如何验证这个数组？例如：
$validatedData = validate([
'id' => 1,
'body' => 'text'
], [
'id' => 'required',
'body' => 'required'
]);
采纳答案by Amr Aly
You can achieve this by create request object like so:
您可以通过像这样创建请求对象来实现这一点：
$request = new Request([
'id' => 1,
'body' => 'text'
]);
$this->validate($request, [
'id' => 'required',
'body' => 'required'
]);
and thus you will get all the functionality of the Request class
因此您将获得 Request 类的所有功能
回答by Ariel Pepito
Should be. Because $request->all()hold all input data as an array .
应该。因为$request->all()将所有输入数据保存为一个数组。
$input = [
'title' => 'testTitle',
'body' => 'text'
];
$input is your customs array.
$validator = Validator::make($input, [
'title' => 'required|unique:posts|max:255',
'body' => 'required',
]);
回答by Muhammad Nauman
Validator::make expects array and not a request object. You can pass any array and implements the rules on it.
Validator::make 需要数组而不是请求对象。您可以传递任何数组并在其上实现规则。
Validator::make(['name' => 'Tom'], ['name' => 'required', 'id' => 'required']);
And it will validate the array. So $request object is not necessary.
它将验证数组。所以 $request 对象不是必需的。
回答by Anas K
$request->all()is array not request object.
This code will work:
$request->all()是数组不是请求对象。此代码将起作用：
$data = [
'id' => 1,
'body' => 'text'
];
$validator = Validator::make($data, [
'id' => 'required',
'body' => 'required',
]);
回答by omarjebari
You can also merge data with the request object:
您还可以将数据与请求对象合并：
$data = ['id' => 1];
$request->merge($data);
Then validate as per usual.
然后照常验证。
