格式化日期字符串以在 JAVA 中删除时间
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Format date string to remove time in JAVA
提问by dsi
Example, String value is:
示例，字符串值为：
15/08/2013 15:30 GMT+10:00
I want to format above string to 15/08/2013(remove time part and only keep date) in Java.
我想15/08/2013在 Java 中将上面的字符串格式化为（删除时间部分并只保留日期）。
How can I do this format?
我怎样才能做到这种格式？
采纳答案by Suresh Atta
Remove time part and only keep date
删除时间部分，只保留日期
String dateString= "15/08/2013 15:30 GMT+10:00";
String result = dateString.split(" ")[0];
That gives you 15/08/2013
那给你 15/08/2013
There is no need to formatter, I guess.
我想不需要格式化程序。
回答by vcetinick
Check out the DateFormat class, http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html
查看 DateFormat 类， http://docs.oracle.com/javase/7/docs/api/java/text/SimpleDateFormat.html
You should be able to parse in the date using a parser and then write out your desired format in another pattern
您应该能够使用解析器解析日期，然后以另一种模式写出所需的格式
i.e. new SimpleDateFormat("dd/MM/yyyy hh:mm z") for inbound
即新的 SimpleDateFormat("dd/MM/yyyy hh:mm z") 用于入站
new SimpleDateFormat("dd/MM/yyyy") for your updated format
new SimpleDateFormat("dd/MM/yyyy") 为您更新的格式
回答by Lefteris Laskaridis
Try using the SimpleDateFormat class: http://docs.oracle.com/javase/7/docs/api/java/text/DateFormat.html
尝试使用 SimpleDateFormat 类：http: //docs.oracle.com/javase/7/docs/api/java/text/DateFormat.html
回答by Jesper
If this is nothing more than you have a string containing 15/08/2013 15:30 GMT+10:00and you just want the date part, which is the first 10 characters of the string, I'd just take the first 10 characters; no need to parse and format it as a date:
如果这只不过是一个包含字符串的字符串，15/08/2013 15:30 GMT+10:00而您只想要日期部分，即字符串的前 10 个字符，我只取前 10 个字符；无需解析并将其格式化为日期：
String input = "15/08/2013 15:30 GMT+10:00";
String result = input.substring(0, 10);
回答by Ran Adler
DateFormat formatter = new SimpleDateFormat(format);
Date date = (Date) formatter.parse(dateStr);
回答by MadProgrammer
2018
2018年
Since it's now 2018 and we have the date/time API in Java 8+ (and the ThreeTen Backport), you could do something like...
由于现在是 2018 年，而且我们在 Java 8+（和ThreeTen Backport）中有日期/时间 API ，你可以做类似的事情......
String text = "15/08/2013 15:30 GMT+10:00";
LocalDateTime ldt = LocalDateTime.parse(text, DateTimeFormatter.ofPattern("dd/MM/yyyy HH:mm z", Locale.ENGLISH));
System.out.println(ldt);
// In case you just want to do some "date" manipulation, without the time component
LocalDate ld = ldt.toLocalDate();
// Will produce "2013-08-15"
//String format = ldt.format(DateTimeFormatter.ISO_LOCAL_DATE);
String format = ldt.format(DateTimeFormatter.ofPattern("dd/MM/yyyy"));
System.out.println(format);
Original Answer
原答案
One approach would be to parse the Stringdate to a Dateobject and then simply format as per your requirements
一种方法是将String日期解析为Date对象，然后根据您的要求简单地格式化
String text = "15/08/2013 15:30 GMT+10:00";
SimpleDateFormat inFormat = new SimpleDateFormat("dd/MM/yyyy HH:mm z");
Date date = inFormat.parse(text);
System.out.println(date);
SimpleDateFormat outFormat = new SimpleDateFormat("dd/MM/yyyy");
String formatted = outFormat.format(date);
System.out.println(formatted);
This has the nice benefit of preserving the date/time information in the Dateshould you need it for other things ;)
Date如果您需要它来做其他事情，这有一个很好的好处，可以保留日期/时间信息；)
See, SimpleDateFormatfor more details
请参阅，SimpleDateFormat了解更多详情
