最简单的 python 相当于 R 的 gsub
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simplest python equivalent to R's gsub
提问by Deena
Is there a simple/one-line python equivalent to R's gsubfunction?
是否有与 Rgsub函数等效的简单/单行 python ？
strings = c("Important text, !Comment that could be removed", "Other String")
gsub("(,[ ]*!.*)$", "", strings)
# [1] "Important text" "Other String"
回答by Nick Becker
For a string:
对于字符串：
import re
string = "Important text, !Comment that could be removed"
re.sub("(,[ ]*!.*)$", "", string)
Since you updated your question to be a list of strings, you can use a list comprehension.
由于您将问题更新为字符串列表，因此您可以使用列表理解。
import re
strings = ["Important text, !Comment that could be removed", "Other String"]
[re.sub("(,[ ]*!.*)$", "", x) for x in strings]
回答by Benjamin Atkin
gsubis the normal subin python - that is, it does multiple replacements by default.
gsubsub在 python 中是正常的——也就是说，默认情况下它会进行多次替换。
The method signature for re.subis sub(pattern, repl, string, count=0, flags=0)
方法签名re.sub是sub(pattern, repl, string, count=0, flags=0)
If you want it to do a single replacement you specify count=1:
如果您希望它执行单个替换，请指定count=1：
In [2]: re.sub('t', 's', 'butter', count=1)
Out[2]: 'buster'
re.Iis the flag for case insensitivity:
re.I是不区分大小写的标志：
In [3]: re.sub('here', 'there', 'Here goes', flags=re.I)
Out[3]: 'there goes'
You can pass a function that takes a match object:
您可以传递一个接受匹配对象的函数：
In [13]: re.sub('here', lambda m: m.group().upper(), 'Here goes', flags=re.I)
Out[13]: 'HERE goes'
