如何在python中将字典项作为函数参数传递？
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How to pass dictionary items as function arguments in python?
提问by Patrick
My code
我的代码
1st file:
第一个文件：
data = {'school':'DAV', 'standard': '7', 'name': 'abc', 'city': 'delhi'}
my_function(*data)
2nd file:
第二个文件：
my_function(*data):
schoolname = school
cityname = city
standard = standard
studentname = name
in the above code, only keys of "data" dictionary were get passed to my_function(), but i want key-value pairs to pass. How to correct this ?
在上面的代码中，只有“数据”字典的键被传递给my_function()，但我想要键值对传递。如何纠正这个？
I want the my_function()to get modified like this
我希望my_function()像这样修改
my_function(school='DAV', standard='7', name='abc', city='delhi')
and this is my requirement, give answers according to this
这是我的要求，根据这个给出答案
EDIT:dictionary key classis changed to standard
编辑：字典键类更改为标准
采纳答案by RemcoGerlich
If you want to use them like that, define the function with the variable names as normal:
如果您想像这样使用它们，请正常定义具有变量名称的函数：
def my_function(school, standard, city, name):
schoolName = school
cityName = city
standardName = standard
studentName = name
Now you can use **when you callthe function:
现在您可以**在调用函数时使用：
data = {'school':'DAV', 'standard': '7', 'name': 'abc', 'city': 'delhi'}
my_function(**data)
and it will work as you want.
它会按你的意愿工作。
P.S.Don't use reserved words such as class.(e.g., use klassinstead)
PS不要使用保留字，例如class.（例如，klass改为使用）
回答by Jakob Bowyer
You can just pass it
你可以通过它
def my_function(my_data):
my_data["schoolname"] = "something"
print my_data
or if you really want to
或者如果你真的想
def my_function(**kwargs):
kwargs["schoolname"] = "something"
print kwargs
回答by venpa
*data interprets arguments as tuples, instead you have to pass **data which interprets the arguments as dictionary.
*data 将参数解释为元组，而您必须传递 **data 将参数解释为字典。
data = {'school':'DAV', 'class': '7', 'name': 'abc', 'city': 'pune'}
def my_function(**data):
schoolname = data['school']
cityname = data['city']
standard = data['class']
studentname = data['name']
You can call the function like this:
你可以这样调用函数：
my_function(**data)
