C语言 如何比较 ASCII 值
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How to compare an ASCII value
提问by XIIIX
I want to store the ASCII value of a letter into a variable, how can I do this?
我想将一个字母的 ASCII 值存储到一个变量中，我该怎么做？
for example :
例如 ：
r ASCII variable = 82
main()
{
character = "character read from a file";
variable= "r ascii"; //(in this case 82), the problem is that the letter is always variable.;
printf( "the value of %c is %d, character, variable)
}
How can I do this?
我怎样才能做到这一点？
Also on an extra note, how could I read a .txtfile character by character? so It could be saved on the character variable.
另外要注意的是，我如何.txt逐个字符地读取文件？所以它可以保存在字符变量上。
回答by Pablo Santa Cruz
Just do:
做就是了：
if (r == 82) {
// provided r is a char or int variable
}
In C, charvariables are represented by their ASCIIinteger value, so, if you have this:
在C 中，char变量由它们的ASCII整数值表示，所以，如果你有这个：
char r;
r = 82;
if (r == 82) {
}
Is the same as:
是相同的：
char r;
r = 'R';
if (r == 'R') { // 'R' value is 82
}
You can even mix them:
你甚至可以混合它们：
char r;
r = 82;
if (r == 'R') { // will be true
}
回答by bijin
If you just want to save the asciivalue onto an integer variable
如果您只想将ascii值保存到整数变量中
just use this
就用这个
int b;
char c = 'r';
b = (int)c;
printf("%d",b);
