jQuery 选中的复选框属性为真，但未显示勾号
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Check box attributes checked is true, but tick is not shown
提问by gotqn
I have two check boxes, that I want to make to behave like they are radio buttons (only one of them is checked at time).
我有两个复选框，我想让它们表现得像单选按钮（一次只选中其中一个）。
So, I have easy found a jQuery solution that should do the trick:
所以，我很容易找到了一个应该可以解决问题的 jQuery 解决方案：
$("input:checkbox").click(function(){
var group = "input:checkbox[name='"+$(this).attr("name")+"']";
$(group).attr("checked",false);
$(this).attr("checked",true);
});
The HTML looks like this:
HTML 如下所示：
<div class="radio">
<label for="q_is_active_true">Is active</label>
<input name="radio_buttons" type="hidden" value="0"><input id="q_is_active_true" name="radio_buttons" type="checkbox" value="1">
<label for="q_is_active_false">Is not active</label>
<input name="radio_buttons" type="hidden" value="0"><input id="q_is_active_false" name="radio_buttons" type="checkbox" value="1">
</div>
But when I click on one of the check boxes, even its "check" attribute is set to "checked" no tick is shown:
但是当我点击其中一个复选框时，即使它的“check”属性设置为“checked”也不会显示勾号：
回答by dsgriffin
回答by Lalit Narayan Mishra
You can try it this way :
你可以这样试试：
$('input[name=checkBoxName]').parents('span').addClass("checked");
$("input[name=checkBoxName]").prop('checked', 'checked');
The first line is to display the tick in the check box and the second line is to actually check it.
第一行是在复选框中显示勾号，第二行是实际勾选它。
