php 为什么 array_diff() 给出 Array 到字符串转换错误?
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Why array_diff() gives Array to string conversion error?
提问by user2963765
I get array to string conversion error for the following line:
我收到以下行的数组到字符串转换错误:
$diff = array_diff($stockist, $arr);
Here, $arr
is an array decoded from a JSON file. Using the is_array()
function I was able to verify that both parameters are arrays. Can someone point me the problem
这$arr
是一个从 JSON 文件解码的数组。使用该is_array()
函数,我能够验证两个参数都是数组。有人能指出我的问题吗
$stockist = array();
while (!feof($file_handle)) {
$line_of_text = fgetcsv($file_handle);
$query = "SELECT * FROM reorderchart WHERE medicine = '"
. trim($line_of_text[3])
. "' ORDER BY medicine";
$result = mysql_query($query);
if (trim($line_of_text[2]) - trim($line_of_text[1]) <= 0) {
while ($row = mysql_fetch_array($result)) {
$file = "results.json";
$arr = json_decode(file_get_contents($file),true);
$pharmacy = trim($row['Medicine']);
if (isset($stockist[$pharmacy])) {
$medicine = $stockist[$pharmacy];
$medicine[] = trim($row['Stockist']);
$stockist[$pharmacy] = $medicine;
} else {
$medicine = array();
$medicine[] = trim($row['Stockist']);
$stockist[$pharmacy] = $medicine;
}
}
}
}
$diff = array();
$diff = array_diff_assoc($stockist,$arr);
ksort($diff);
foreach ($diff as $key => $value) {
echo "<table align='center' border='1'>";
echo "<tr><td align = 'center'> <font color = 'blue'> $key</td></tr>";
foreach($value as $key1 => $value1) {
echo "<tr><td align ='center'>$value1</td></tr><br>";
}
echo "</table>";
}
回答by Viacheslav Kondratiuk
According to it:
根据它:
php -r 'array_diff(array("a" => array("b" => 4)), array(1));'
PHP Notice: Array to string conversion in Command line code on line 1
PHP Stack trace:
PHP 1. {main}() Command line code:0
PHP 2. array_diff() Command line code:1
One of your arrays is multidimensional.
您的数组之一是多维的。
array_diff
only checks one dimension of a n-dimensional array. Of course you can check deeper dimensions by using array_diff($array1[0], $array2[0]);
array_diff
只检查 n 维数组的一维。当然,您可以使用以下方法检查更深的维度array_diff($array1[0], $array2[0]);
回答by E.A.T
Yes, the strict answer is because "One of your arrays is multidimensional."
是的,严格的答案是因为“你的一个数组是多维的。”
Another useful note might be - depending on your needs of further parsing the actual differences- consider first testing your arrays with:
另一个有用的注意事项可能是 -根据您进一步解析实际差异的需要- 考虑首先使用以下方法测试您的数组:
$diff = strcmp(json_encode($stockist), json_encode($arr));
or
或者
$diff = strspn(json_encode($stockist) ^ json_encode($arr), "$diff = xdiff_string_diff(json_encode($stockist), json_encode($arr));
");
or
或者
while ($arr) {
list($key, $value) = each($arr);
is_array($value) ? $arr = $value : $out[$key] = $value;
unset($arr[$key]);
}
// Now $out is flatten version of $arr.
All these options will compare the entire array tree, not just the top level.
所有这些选项将比较整个数组树,而不仅仅是顶层。
回答by kenorb
Since array_diff
can only deals with one dimension, you can either:
由于array_diff
只能处理一维,您可以:
convert your multi-dimentional array into one dimension, e.g. by:
flattening a multidimensional array, e.g.:
$results = array_diff(array_map('serialize',$a2), array_map('serialize',$a1));
serializing the array, e.g.:
while ($arr) { list($key, $value) = each($arr); is_array($value) ? $arr = $value : $out[$key] = $value; unset($arr[$key]); } // Now $out is flatten version of $arr.
use custom recursive
array_diff
-like function,
将您的多维数组转换为一维,例如:
展平一个多维数组,例如:
$results = array_diff(array_map('serialize',$a2), array_map('serialize',$a1));
序列化数组,例如:
function arrayRecursiveDiff($aArray1, $aArray2) { $aReturn = array(); foreach ($aArray1 as $mKey => $mValue) { if (array_key_exists($mKey, $aArray2)) { if (is_array($mValue)) { $aRecursiveDiff = arrayRecursiveDiff($mValue, $aArray2[$mKey]); if (count($aRecursiveDiff)) { $aReturn[$mKey] = $aRecursiveDiff; } } else { if ($mValue != $aArray2[$mKey]) { $aReturn[$mKey] = $mValue; } } } else { $aReturn[$mKey] = $mValue; } } return $aReturn; }
使用自定义递归
array_diff
类函数,
回答by max
According to PHP documentation for the function
根据该函数的 PHP 文档
Note: Two elements are considered equal if and only if (string) $elem1 === (string) $elem2. In words: when the string representation is the same.
注意:当且仅当 (string) $elem1 === (string) $elem2 时才认为两个元素相等。换句话说:当字符串表示相同时。
For more information refer to http://php.net/manual/en/function.array-diff.php
回答by Jim Wright
You can see in the array_diff() documentationthat:
您可以在array_diff() 文档中看到:
Two elements are considered equal if and only if (string) $elem1 === (string) $elem2. In other words: when the string representation is the same.
当且仅当 (string) $elem1 === (string) $elem2 时才认为两个元素相等。换句话说:当字符串表示相同时。
So it looks like you can't use this function with multi dimensional array, or in fact any value that cannot be converted to a string. This is because the function will cast values to a string
to do the comparison.
所以看起来你不能将此函数用于多维数组,或者实际上任何无法转换为字符串的值。这是因为该函数会将值转换为 astring
来进行比较。
You can write your own function to recursively check arrays for a difference - in fact the following is from the comments of the docs linked above.
您可以编写自己的函数来递归检查数组的差异 - 事实上,以下内容来自上面链接的文档的评论。
You can see the comment here.
$diff = strcmp(serialize($arr1), serialize($arr2))
回答by Trendfischer
I've got the same error and found the following bug report for php:
我遇到了同样的错误,并发现了以下 php 错误报告:
https://bugs.php.net/bug.php?id=60198
https://bugs.php.net/bug.php?id=60198
Some of the array_* functions that compare elements in multiple arrays do so by (string)$elem1 === (string)$elem2.
If $elem1 or $elem2 is an array, then the array to string notice is thrown.
Two examples of functions that can throw this are array_intersect() and array_diff().
If these functions are not expected to take arrays with other arrays as values, this should be mentioned on the documentation pages.
一些用于比较多个数组中元素的 array_* 函数是通过 (string)$elem1 === (string)$elem2 来实现的。
如果 $elem1 或 $elem2 是一个数组,则抛出数组到字符串通知。
可以抛出 this 的两个函数示例是 array_intersect() 和 array_diff()。
如果这些函数不希望将具有其他数组的数组作为值,则应在文档页面中提及。
That report describes, why php throws an error on comparing a multi-dimensional array.
该报告描述了为什么 php 在比较多维数组时会抛出错误。
回答by A. Fül?p
What about my solution:
我的解决方案呢:
$a1 = [
'foo' => 'bar',
'bar' => [
'test' => 'test'
],
'foobar' => 'fizzbuzz'
];
$a2 = [
'foobar' => 'fizzbuzz',
'herp' => [
'derp' => 'herpderp'
]
];
$diff = array_diff(array_map('serialize', $a1), array_map('serialize', $a2));
$multidimensional_diff = array_map('unserialize', $diff);
print_r($multidimensional_diff);
回答by ZhuRenTongKu
Came across this one while working on a platform upgrade for PHP 7.3 from 5.3 today... Since I'm storing this value for use later on, I wanted to be sure I didn't wind up with a 'partially' serialized array that may break things downstream.
今天在为 PHP 7.3 从 5.3 进行平台升级时遇到了这个问题......因为我存储了这个值供以后使用,我想确保我没有得到一个“部分”序列化的数组可能会破坏下游的东西。
Thanks kenorb for getting me onto the right path (I upvoted ur answer). The following is working nicely for me.
感谢 kenorb 让我走上正确的道路(我赞成你的答案)。以下对我来说效果很好。
Code:
代码:
Array
(
[foo] => bar
[bar] => Array
(
[test] => test
)
)
Output:
输出:
array_diff_assoc
回答by TheBlueAssasin
This is my solution for a similar problem. I want to compare two associative arrays and return the changed values, but some of the elements are arrays. So if I use
这是我对类似问题的解决方案。我想比较两个关联数组并返回更改后的值,但有些元素是数组。所以如果我使用
public static $example1 = [
'id' => 1,
'status' => 2,
'elements' => ['test', 'example'],
'different' => ['old' => 5, 'new' => 9]
];
public static $example2 = [
'id' => 1,
'status' => 3,
'elements' => ['test', 'example'],
'different' => ['old' => 5, 'new' => 8]
];
public static function test(){
die(var_dump(self::udiffAssoc(self::$example1, self::$example2)));
}
public static function udiffAssoc(array $array1, array $array2)
{
$checkDiff = function ($a, $b) use (&$checkDiff) {
if (is_array($a) && is_array($b)) {
return array_udiff_assoc($a, $b, $checkDiff);
} elseif (is_array($a)) {
return 1;
} elseif (is_array($b)) {
return -1;
} elseif ($a === $b) {
return 0;
} else {
return $a > $b ? 1 : -1;
}
};
return array_udiff_assoc($array1, $array2, $checkDiff);
}
, it gives me "Array to string error". My function will also compare the elements which are arrays and if there's a difference, it will return the array element. It is still a work in progress and not tested extensively. For example:
,它给了我“数组到字符串错误”。我的函数还将比较数组元素,如果有差异,它将返回数组元素。它仍在进行中,尚未经过广泛测试。例如:
array(2) {
["status"]=>
int(2)
["different"]=>
array(2) {
["old"]=>
int(5)
["new"]=>
int(9)
}
}
if you run ::test it will return:
如果您运行 ::test 它将返回:
##代码##