C# 如何将按钮从一个面板拖放到另一个面板？
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How to drag and drop a button from one panel to another panel?
提问by Ranjan Panigrahi
I have 5 panels in a form and two buttons in two different panels, now the requirement is to move the buttons from one panel to another.
我在一个表单中有 5 个面板，在两个不同的面板中有两个按钮，现在需要将按钮从一个面板移动到另一个面板。
Please suggest me a code.
请给我建议一个代码。
采纳答案by LarsTech
For demonstration, place two panels on a form and a button in one of the panels:
为了演示，将两个面板放在一个窗体上，并在其中一个面板中放置一个按钮：
public Form1() {
InitializeComponent();
panel1.AllowDrop = true;
panel2.AllowDrop = true;
panel1.DragEnter += panel_DragEnter;
panel2.DragEnter += panel_DragEnter;
panel1.DragDrop += panel_DragDrop;
panel2.DragDrop += panel_DragDrop;
button1.MouseDown += button1_MouseDown;
}
void button1_MouseDown(object sender, MouseEventArgs e) {
button1.DoDragDrop(button1, DragDropEffects.Move);
}
void panel_DragEnter(object sender, DragEventArgs e) {
e.Effect = DragDropEffects.Move;
}
void panel_DragDrop(object sender, DragEventArgs e) {
((Button)e.Data.GetData(typeof(Button))).Parent = (Panel)sender;
}
回答by Jess Stuart
This approach also works for Group Boxes, but the MouseEnter, MouseLeave, and MouseUp events must be added manually:
这种方法也适用于分组框，但必须手动添加 MouseEnter、MouseLeave 和 MouseUp 事件：
public frmMain ( ) {
InitializeComponent ( );
pbxMoveIt.BringToFront ( );
gbx1.AllowDrop = true;
gbx2.AllowDrop = true;
lblStatus.Text = "GUI Status: Started";
gbx1.MouseEnter += gbx_MouseEnter;
gbx1.MouseLeave += gbx_MouseLeave;
gbx1.MouseUp += gbx_MouseUp;
gbx2.MouseEnter += gbx_MouseEnter;
gbx2.MouseLeave += gbx_MouseLeave;
gbx2.MouseUp += gbx_MouseUp;
}
private void gbx_MouseEnter ( object sender, EventArgs e ) {
// useful code
// ...
}
private void gbx_MouseLeave ( object sender, EventArgs e ) {
// useful code
// ...
}
private void gbx_MouseUp ( object sender, EventArgs e ) {
// useful code
// ...
}
