php 使用php从以开头和结尾的字符串中获取所有匹配项
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/14308154/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Get all matches from string that start with and end, using php
提问by Jeroen
How would I use PHP to extract everything in between [startstring]and [endstring]from this string:
我怎么会在两者之间使用PHP提取物的一切[startstring]，并[endstring]从该字符串：
[startstring]hello = guys[endstring] hello guys [startstring]jerk = you[endstring] welcome to the universe
I'd like to find all the matches of [startstring]and [endstring], and echo the text inside. Kinda like a delimiter. And I would like all the matches echoed to be seperated by a space.
我想找到[startstring]and 的所有匹配项[endstring]，并回显里面的文本。有点像分隔符。我希望所有回声的匹配项都由一个空格分隔。
How would I go about accomplishing this? Would this require regex? Could you provide a sample?
我将如何实现这一目标？这需要regex吗？你能提供一个样品吗？
Thanks so much! :)
非常感谢！:)
回答by Jeroen
preg_match_all('/\[startstring\](.*?)\[endstring\]/s', $input, $matches);
echo implode(' ', $matches);
preg_match_all('/\[startstring\](.*?)\=(.*?)\[endstring\]/s', $input, $matches);
for ($i = 0; $i < count($matches[1]); $i++) {
$key = $matches[1][$i];
$value = $matches[2][$i];
$$key = $value;
}
回答by hsz
Try with preg_match_all:
preg_match_all('/\[startstring\](.*?)\[endstring\]/', $input, $matches);
var_dump($matches);
