Android 如何在从站点下载和解析 XML 文件时一起使用 Retrofit 和 SimpleXML？

How to use Retrofit and SimpleXML together in downloading and parsing an XML file from a site?

提问by greenspand

I just started working with Retrofit. I am working on a project that uses SimpleXML. Can somebody provide me an example in which one fetches an XML from a site e.g. http://www.w3schools.com/xml/simple.xml" and reads it out?

我刚开始使用 Retrofit。我正在开发一个使用 SimpleXML 的项目。有人可以为我提供一个示例，其中从站点（例如http://www.w3schools.com/xml/simple.xml ）获取 XML并将其读出？

回答by vandus

You will create an interface as a new class in your project:

您将在项目中创建一个接口作为新类：

public interface ApiService {
    @GET("/xml/simple.xml")
    YourObject getUser();
}

Then in your activity you will call the following:

然后在您的活动中，您将调用以下内容：

RestAdapter restAdapter = new RestAdapter.Builder()
                    .setEndpoint("http://www.w3schools.com")
                    .setConverter(new SimpleXmlConverter())
                    .build();

ApiService apiService = restAdapter.create(ApiService.class);
YourObject object = apiService.getXML();

To get your libraries correctly, in your build.gradle file you need to do the following:

要正确获取库，在 build.gradle 文件中，您需要执行以下操作：

configurations {
    compile.exclude group: 'stax'
    compile.exclude group: 'xpp3'
}

dependencies {
    compile fileTree(dir: 'libs', include: ['*.jar'])
    compile 'com.squareup.retrofit:retrofit:1.6.1'
    compile 'com.mobprofs:retrofit-simplexmlconverter:1.1'
    compile 'org.simpleframework:simple-xml:2.7.1'
    compile 'com.google.code.gson:gson:2.2.4'
}

Then you need to specify YourObject and add annotations to it according to the structure of the xml file

然后需要指定YourObject并根据xml文件的结构为其添加注解

@Root(name = "breakfast_menu")
public class BreakFastMenu {
    @ElementList(inline = true)
    List<Food> foodList;
}

@Root(name="food")
public class Food {
    @Element(name = "name")
    String name;

    @Element(name = "price")
    String price;

    @Element(name = "description")
    String description;

    @Element(name = "calories")
    String calories;
}

回答by greenspand

import java.util.ArrayList;
import java.util.List;

import org.simpleframework.xml.ElementList;
import org.simpleframework.xml.Root;

@Root(name = "breakfast_menu")
public class BrakfastMenu
  {
    @ElementList(inline = true)
    protected List<Food> food;

    public List<Food> getConfigurations()
      {
        if (food == null)
          {
            food = new ArrayList<Food>();
          }
        return this.food;
      }

    public void setConfigurations(List<Food> configuration)
      {
        this.food = configuration;
      }

  }

回答by Guillaume Husta

Here's how to do it with Retrofit 2.

下面是如何使用Retrofit 2做到这一点。

First you need an interface like (headers annotations are optional) :

首先，您需要一个类似的接口（标头注释是可选的）：

public interface ApiService
{

    @GET("xml/simple.xml")
    @Headers({"Accept: application/xml",
            "User-Agent: Retrofit-Sample-App"})
    Call<BreakfastMenu> getBreakfastMenu();

}

The annotated POJOs for XML are the same as in the other answers.

XML 的带注释的 POJO 与其他答案中的相同。

Then you need to make a request to the server :

然后你需要向服务器发出请求：

    Retrofit retrofit = new Retrofit.Builder()
            .baseUrl("https://www.w3schools.com/")
            .addConverterFactory(SimpleXmlConverterFactory.create())
            .build();

    ApiService apiService = retrofit.create(ApiService.class);
    Call<BreakfastMenu> call = apiService.getBreakfastMenu();
    Response<BreakfastMenu> response = call.execute();
    // response.code() == 200
    BreakfastMenu breakfastMenu = response.body();

The needed libraries are :

所需的库是：

• retrofit 2.3.0
• okhttp 3.8.0
• converter-simplexml 2.3.0
• simple-xml 2.7.1
• Java 7

• 改造 2.3.0
• 好http 3.8.0
• 转换器-simplexml 2.3.0
• 简单的 xml 2.7.1
• 爪哇 7

Source available on my GitHub

可在我的 GitHub 上找到源代码