php 使用ajax jquery刷新页面而不使用重新加载功能
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refresh page with ajax jquery without use of reload function
提问by Ronak Patel
I am performing delete records by using jquery ajax in php. I want to refresh that content without the use of location.reload() function. I tried this,
我正在通过在 php 中使用 jquery ajax 执行删除记录。我想在不使用 location.reload() 函数的情况下刷新该内容。我试过这个，
$("#divSettings").html(this);
but, it's not working. What's the correct logic to get updated content in div. Thanks.
但是，它不起作用。在 div 中获取更新内容的正确逻辑是什么。谢谢。
Code:
代码：
function deletePoll(postId){
$.ajax({
type: "POST",
url: "../internal_request/ir_display_polls.php",
data: {
postId: postId
},
success: function(result) {
location.reload();
//$("#divSettings").html(this);
}
});
}
回答by kelunik
You're almost there:
您快到了：
function deletePoll(postId){
$.ajax({
type: "POST",
url: "../internal_request/ir_display_polls.php",
data: {
postId: postId
},
success: function(result) {
$("#divSettings").html(result); // <-- result must be your html returned from ajax response
}
});
}
回答by Paul Gleeson
You just needed to set the result into your '#divSettings' element using the .html() function :
您只需要使用 .html() 函数将结果设置到您的“#divSettings”元素中：
$('#divSettings').html(result);
So a full example would look like :
所以一个完整的例子看起来像：
function deletePoll(postId){
$.ajax({
type: "POST",
url: "../internal_request/ir_display_polls.php",
data: {
postId: postId
},
success: function(result) {
//Sets your content into your div
$('#divSettings').html(result);
}
});
}
回答by Harsh
I believe you have to clear the section first and then you can attach the HTML again. Like
我相信您必须先清除该部分，然后才能再次附加 HTML。喜欢
function deletePoll(postId){
$.ajax({
type: "POST",
url: "../internal_request/ir_display_polls.php",
data: {
postId: postId
},
success: function(result) {
//Sets your content into your div
$('#divSettings').html("");
$('#divSettings').html(result);
}
});
}
I believe this way you won't see the old content.
我相信这样你就不会看到旧的内容。
