java.lang.IllegalArgumentException: setAttribute: 不可序列化的属性
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java.lang.IllegalArgumentException: setAttribute: Non-serializable attribute
提问by Jon Skeet
I have inherited some code and am getting an error when I try to run it. The error is below:
我继承了一些代码，但在尝试运行它时出现错误。错误如下：
10:08:32,093 ERROR [MyServlet]:260 - Servlet.service() for servlet MyServlet threw exception
java.lang.IllegalArgumentException: setAttribute: Non-serializable attribute
at org.apache.catalina.session.StandardSession.setAttribute(StandardSession.java:1270)
at org.apache.catalina.session.StandardSession.setAttribute(StandardSession.java:1248)
at org.apache.catalina.session.StandardSessionFacade.setAttribute(StandardSessionFacade.java:130)
at uk.co.my.servlet.MyServlet.doPost(MyServlet.java:121)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:647)
at javax.servlet.http.HttpServlet.service(HttpServlet.java:729)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:269)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188)
at com.my.ddi.security.SecurityContextServletFilter.doFilter(SecurityContextServletFilter.java:55)
at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:215)
at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:188)
at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:213)
at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:172)
at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:433)
at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127)
at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:117)
at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:108)
at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:174)
at org.apache.coyote.http11.Http11AprProcessor.process(Http11AprProcessor.java:835)
at org.apache.coyote.http11.Http11AprProtocol$Http11ConnectionHandler.process(Http11AprProtocol.java:640)
at org.apache.tomcat.util.net.AprEndpoint$Worker.run(AprEndpoint.java:1286)
at java.lang.Thread.run(Unknown Source)
I imagine that the main problem is where it is hitting my code at uk.co.my.servlet.MyServlet.doPost(MyServlet.java:172). Line 121 of MyServlet is session.setAttribute("LISTENER", myListener);
我想主要问题是它在 uk.co.my.servlet.MyServlet.doPost(MyServlet.java:172) 上遇到了我的代码。MyServlet 的第 121 行是 session.setAttribute("LISTENER", myListener);
This myListener object is from the following class:
这个 myListener 对象来自以下类：
public class myListener {
static Log log = LogFactory.getLog(TerminationListener.class.getName());
private boolean shouldCancel = false;
How would I go about getting rid of this error? Would I need to use the transient keyword?
我将如何摆脱这个错误？我需要使用transient关键字吗？
回答by Jon Skeet
If you want an instance of myListenerto be placed in a session, you need to make it serializable. That mightinvolve making some fields transient, but then those fields won't be saved in the session. You'll also need to make the class implement Serializable.
如果要将 的实例myListener放置在会话中，则需要使其可序列化。这可能涉及使某些字段成为瞬态，但这些字段将不会保存在会话中。您还需要使类实现Serializable。
I suggest you look at the documentation for Serializable, which goes into a fair amount of detail about serialization.
我建议您查看Serializable的文档，其中详细介绍了有关序列化的内容。
