未捕获的类型错误：javascript 中的非法调用
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Uncaught TypeError: Illegal invocation in javascript
提问by fcortes
I'm creating a lambda function that executes a second function with a concrete params.This code works in Firefox but not in Chrome, its inspector shows a weird error, Uncaught TypeError: Illegal invocation. What's wrong of my code?
我正在创建一个 lambda 函数，该函数使用具体参数执行第二个函数。此代码在 Firefox 中有效，但在 Chrome 中无效，其检查器显示一个奇怪的错误，Uncaught TypeError: Illegal invocation。我的代码有什么问题？
var make = function(callback,params){
callback(params);
}
make(console.log,'it will be accepted!');
回答by Paul
The console's log function expects thisto refer to the console (internally). Consider this code which replicates your problem:
控制台的日志功能期望this引用控制台（内部）。考虑这个复制你的问题的代码：
var x = {};
x.func = function(){
if(this !== x){
throw new TypeError('Illegal invocation');
}
console.log('Hi!');
};
// Works!
x.func();
var y = x.func;
// Throws error
y();
Here is a (silly) example that will work, since it binds thisto consolein your make function:
这是一个可以工作的（愚蠢的）示例，因为它绑定this到console您的 make 函数中：
var make = function(callback,params){
callback.call(console, params);
}
make(console.log,'it will be accepted!');
This will also work
这也将起作用
var make = function(callback,params){
callback(params);
}
make(console.log.bind(console),'it will be accepted!');
回答by ifreedom
You can wrap the function which need 'this' to a new lambda function, and then use it for your callback function.
您可以将需要“this”的函数包装到新的 lambda 函数中，然后将其用于回调函数。
function make(callback, params) {
callback(params);
}
make(function(str){ console.log(str); }, 'it will be accepted!');
