python 在 django 中运行普通 sql 查询时如何获取字段名称

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时间:2020-11-03 20:53:18  来源:igfitidea点击:

How to get field names when running plain sql query in django

pythondjango

提问by Sergey Golovchenko

In one of my django views I query database using plain sql (not orm) and return results.

在我的 Django 视图之一中,我使用普通 sql(不是 orm)查询数据库并返回结果。

sql = "select * from foo_bar"
cursor = connection.cursor()
cursor.execute(sql)
rows = cursor.fetchall()

I am getting the data fine, but not the column names. How can I get the field names of the result set that is returned?

我得到的数据很好,但不是列名。如何获取返回的结果集的字段名称?

回答by ZAD-Man

On the Django docs, there's a pretty simple method provided (which does indeed use cursor.description, as Ignacio answered).

Django docs 上,提供了一个非常简单的方法(它确实使用了cursor.description,正如 Ignacio 回答的那样)。

def dictfetchall(cursor):
    "Return all rows from a cursor as a dict"
    columns = [col[0] for col in cursor.description]
    return [
        dict(zip(columns, row))
        for row in cursor.fetchall()
    ]

回答by Ignacio Vazquez-Abrams

According to PEP 249, you can try using cursor.description, but this is not entirely reliable.

根据PEP 249,您可以尝试使用cursor.description,但这并不完全可靠。

回答by Hey Teacher

I have found a nice solution in Doug Hellmann's blog:

我在 Doug Hellmann 的博客中找到了一个不错的解决方案:

http://doughellmann.com/2007/12/30/using-raw-sql-in-django.html

http://doughellmann.com/2007/12/30/using-raw-sql-in-django.html

from itertools import *
from django.db import connection

def query_to_dicts(query_string, *query_args):
    """Run a simple query and produce a generator
    that returns the results as a bunch of dictionaries
    with keys for the column values selected.
    """
    cursor = connection.cursor()
    cursor.execute(query_string, query_args)
    col_names = [desc[0] for desc in cursor.description]
    while True:
        row = cursor.fetchone()
        if row is None:
            break
        row_dict = dict(izip(col_names, row))
        yield row_dict
    return

Example usage:

用法示例:

  row_dicts = query_to_dicts("""select * from table""") 

回答by user12231804

try the following code :

尝试以下代码:

def read_data(db_name,tbl_name): 
    details = sfconfig_1.dbdetails
    connect_string = 'DRIVER=ODBC Driver 17 for SQL Server;SERVER={server}; DATABASE={database};UID={username}\
        ;PWD={password};Encrypt=YES;TrustServerCertificate=YES'.format(**details)

    connection = pyodbc.connect(connect_string)#connecting to the server
    print("connencted to db")
    # query syntax 

    query = 'select top 100 * from '+'[{}].[dbo].[{}]'.format(db_name,tbl_name) + ' t where t.chargeid ='+ "'622102*3'"+';'
    #print(query,"\n")
    df    = pd.read_sql_query(query,con=connection)
    print(df.iloc[0])

    return "connected to db...................."