如何只从 PHP 字符串中取出数字？
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How Do I Take Out Only Numbers From A PHP String?
提问by mehulmpt
Suppose, I have this string:
假设，我有这个字符串：
$string = "Hello! 123 How Are You? 456";
I want to set variable $intto $int = 123456;
我想将变量设置$int为$int = 123456;
How do I do it?
我该怎么做？
Example 2:
示例 2：
$string = "12,456";
Required:
必需的：
$num = 12456;
Thank you!
谢谢！
回答by I?ya Bursov
Correct variant will be:
正确的变体将是：
$string = "Hello! 123 How Are You? 456";
$int = intval(preg_replace('/[^0-9]+/', '', $string), 10);
回答by Fopa Léon Constantin
You can use this method to select only digit present in your text
您可以使用此方法仅选择文本中存在的数字
function returnDecimal($text) {
$tmp = "";
for($text as $key => $val) {
if($val >= 0 && $val <= 9){
$tmp .= $val
}
}
return $tmp;
}
回答by Shankar Damodaran
Use this regular expression !\d!
使用这个正则表达式 !\d!
<?php
$string = "Hello! 123 How Are You? 456";
preg_match_all('!\d!', $string, $matches);
echo (int)implode('',$matches[0]);
回答by Miroslav Gorchev
You can use the below:
您可以使用以下内容：
$array = [];
preg_match_all('/-?\d+(?:\.\d+)?+/', $string, $array);
Where $string is the entered string and $array is where each number(not digit!,including also negative values!) is loaded and available for different more operations.
$string 是输入的字符串，$array 是每个数字（不是数字！，也包括负值！）的加载位置，可用于不同的更多操作。
