php MySQL 在哪里不在名称数组中？
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时间：2020-08-25 03:05:51 来源:igfitidea点击:
MySQL where NOT IN name array?
提问by Karem
I would like to exclude these albums, that has name:
我想排除这些具有名称的专辑：
$ban_album_names = array('Wall', 'Profile', 'Cover', 'Instagram');
How do I write correctly,
怎么写才正确
SELECT * FROM albums WHERE name NOT IN ???
How can I make it look in the array, and if the name matches it should != the row
我怎样才能让它在数组中查找，如果名称匹配，它应该 != 行
回答by hjpotter92
Try this:
尝试这个：
$sql = "SELECT *
FROM albums
WHERE name NOT IN ( '" . implode( "', '" , $ban_album_names ) . "' )";
回答by catalinux
The MySQL CODE is
MySQL 代码是
SELECT * FROM albums WHERE name NOT IN ('Wall', 'Profile', 'Cover', 'Instagram')
