jQuery - 如何查找 id 是否具有特定字符串？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/640903/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
jQuery - how can I find if an id has a specific string?
提问by AndreMiranda
I have a table and I want to know if its last td its id contains a certain string. For example, if my last td has id "1234abc", I want to know if this id contains "34a". And I need to do that in a 'if' statement.
我有一张表，我想知道它的最后一个 td 是否包含某个字符串。例如，如果我的最后一个 td 的 id 为“1234abc”，我想知道这个 id 是否包含“34a”。我需要在“if”语句中做到这一点。
if(myLastTdId Contains "blablabla"){ do something }
if(myLastTdId 包含“blablabla”){ 做某事 }
Thanks!!!
谢谢！！！
回答by CMS
You could use the "attributeContains" selector:
您可以使用“ attributeContains”选择器：
if($("#yourTable td:last-child[id*='34a']").length > 0) {
//Exists, do something...
}
回答by Paolo Bergantino
This is easily done with indexOfand last-child.
这很容易用indexOf和完成last-child。
<table id='mytable'>
<tr>
<td id='abc'></td>
<td id='cde'></td>
</tr>
</table>
<script>
if($('#mytable td:last-child').attr('id').indexOf('d') != -1) {
alert('found!');
}
</script>
Here it would alert 'found' because dappears in the string cde
在这里它会提醒“找到”，因为d出现在字符串中cde
回答by Ben Blank
If your tdis "bare" (i.e. not wrapped in a jQuery object), you can access its idattribute directly:
如果您td是“裸机”（即未包装在 jQuery 对象中），您可以id直接访问其属性：
if (myTD.id.indexOf("34a") > -1) {
// do stuff
}
If it isin a jQuery object, you'll need to get it out first:
如果是在一个jQuery对象，你需要首先把它弄出来：
if (jMyTD[0].id.indexOf("34a") > -1 {
// do stuff
}
The indexOffunction finds the offset of one string within another. It returns -1 if the first string doesn't contain the second at all.
该indexOf函数查找一个字符串在另一个字符串中的偏移量。如果第一个字符串根本不包含第二个，则返回 -1。
Edit:
编辑：
On second thought, you may need to clarify your question. It isn't clear which of these you're trying to match "34a" against:
再三考虑，您可能需要澄清您的问题。目前尚不清楚您尝试将“34a”与以下哪些匹配：
<td id="1234abcd">blahblah</td><td id="blahblah">1234abcd</td><table id="1234abcd"><tr><td>blahblah</td></tr></table><table id="blahblah"><tr><td>1234abcd</td></tr></table>
<td id="1234abcd">blahblah</td><td id="blahblah">1234abcd</td><table id="1234abcd"><tr><td>blahblah</td></tr></table><table id="blahblah"><tr><td>1234abcd</td></tr></table>
回答by Scott Evernden
Not completely clear if you mean last td in each tr, or the very last td:
如果您的意思是每个 tr 中的最后一个 td 或最后一个 td，则不完全清楚：
if ($('#myTable td:last[id*=34a]').length) {
...
}
