C语言 如何在循环写入时动态更改文件名？
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How to dynamically change filename while writing in a loop?
提问by Richard Knop
I would like to do something like this: In a loop, first iteration write some content into a file named file0.txt, second iteration file1.txt and so on, just increase the number.
我想做这样的事情：在一个循环中，第一次迭代将一些内容写入名为file0.txt的文件，第二次迭代file1.txt等，只需增加数量。
FILE *img;
int k = 0;
while (true)
{
// here we get some data into variable data
file = fopen("file.txt", "wb");
fwrite (data, 1, strlen(data) , file);
fclose(file );
k++;
// here we check some condition so we can return from the loop
}
回答by Jookia
int k = 0;
while (true)
{
char buffer[32]; // The filename buffer.
// Put "file" then k then ".txt" in to filename.
snprintf(buffer, sizeof(char) * 32, "file%i.txt", k);
// here we get some data into variable data
file = fopen(buffer, "wb");
fwrite (data, 1, strlen(data) , file);
fclose(file );
k++;
// here we check some condition so we can return from the loop
}
回答by PeteUK
A different way to do it in C++:
在 C++ 中执行此操作的另一种方法：
#include <iostream>
#include <fstream>
#include <sstream>
int main()
{
std::string someData = "this is some data that'll get written to each file";
int k = 0;
while(true)
{
// Formulate the filename
std::ostringstream fn;
fn << "file" << k << ".txt";
// Open and write to the file
std::ofstream out(fn.str().c_str(),std::ios_base::binary);
out.write(&someData[0],someData.size());
++k;
}
}
回答by Nils Pipenbrinck
FILE *img;
int k = 0;
while (true)
{
// here we get some data into variable data
char filename[64];
sprintf (filename, "file%d.txt", k);
file = fopen(filename, "wb");
fwrite (data, 1, strlen(data) , file);
fclose(file );
k++;
// here we check some condition so we can return from the loop
}
回答by AndersK
so create the filename using sprintf:
所以使用 sprintf 创建文件名：
char filename[16];
sprintf( filename, "file%d.txt", k );
file = fopen( filename, "wb" ); ...
(although that is a C solution so the tag is not correct)
（虽然这是一个 C 解决方案，所以标签不正确）
回答by Josh Wieder
I accomplished this in the manner below. Note that unlike a few of the other examples, this will actually compile and function as intended by without any modification beside preprocessor includes. The solution below iterates fifty filenames.
我以下面的方式完成了这项工作。请注意，与其他一些示例不同，这实际上将按预期编译和运行，除了预处理器包含外，无需任何修改。下面的解决方案迭代五十个文件名。
int main(void)
{
for (int k = 0; k < 50; k++)
{
char title[8];
sprintf(title, "%d.txt", k);
FILE* img = fopen(title, "a");
char* data = "Write this down";
fwrite (data, 1, strlen(data) , img);
fclose(img);
}
}
