Javascript 正则表达式以任何顺序匹配查询中的所有单词
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Regular Expression to MATCH ALL words in a query, in any order
提问by kayen
I'm trying to build a search feature for a project which narrows down items based on a user search input and if it matches the keywords listed against items. For this, I'm saving the item keywords in a dataattribute and matching the query with these keywords using a RegExp pattern.
我正在尝试为一个项目构建一个搜索功能，该功能根据用户搜索输入缩小项目范围，并且它是否与针对项目列出的关键字相匹配。为此，我将项目关键字保存在data属性中，并使用 RegExp 模式将查询与这些关键字进行匹配。
I'm currently using this expression, which I know is not correct and need your help on that:
我目前正在使用这个表达式，我知道这是不正确的，需要你的帮助：
new RegExp('\\b(' + query + ')', 'gi')))where query is |separated values of the query entered by the user (e.g. \\b(meat|pasta|dinner)). This returns me a match even if there is only 1 match, say for example - meat
new RegExp('\\b(' + query + ')', 'gi')))其中 query 是|用户输入的查询的分隔值（例如\\b(meat|pasta|dinner)）。即使只有 1 个匹配项，这也会返回匹配项，例如 -meat
Just to throw some context, here's a small example:
只是为了抛出一些上下文，这是一个小例子：
If a user types: meat pasta dinnerit should list all items which have ALL the 3 keywords listed against them i.e. meatpastaand dinner. These are independent of the order they're typed in.
如果用户键入：meat pasta dinner它应该列出所有针对它们列出的所有 3 个关键字的项目，即meatpasta和dinner。这些与它们的输入顺序无关。
Can you help me with an expression which will match ALL words in a query, in any order?
你能帮我一个表达式，以任何顺序匹配查询中的所有单词吗？
回答by stema
You can achieve this will lookahead assertions
你可以实现这会先行断言
^(?=.*\bmeat\b)(?=.*\bpasta\b)(?=.*\bdinner\b).+
See it here on Regexr
在 Regexr 上看到它
(?=.*\bmeat\b)is a positive lookahead assertion, that ensures that \bmeat\bis somewhere in the string. Same for the other keywords and the .+is then actually matching the whole string, but only if the assertions are true.
(?=.*\bmeat\b)是一个积极的前瞻断言，确保它\bmeat\b在字符串中的某个地方。其他关键字相同，.+然后实际上匹配整个字符串，但前提是断言为真。
But it will match also on "dinner meat Foobar pasta"
但它也会与“晚餐肉 Foobar 意大利面”相匹配
回答by ColBeseder
your regex looks pretty good:
你的正则表达式看起来不错：
\b(meat|pasta|dinner)\b
Check that the length of matches equals the number of keywords (in this case, three):
检查匹配的长度是否等于关键字的数量（在本例中为三个）：
string.match(re).length === numberOfKeywords
where reis the regex with a gflag, stringis the data and numberOfKeywordsis the number of keywords
哪里re是带g标志的正则表达式，string是数据，numberOfKeywords是关键字的数量
This assumes that there are no repeated keywords.
这假设没有重复的关键字。
回答by prettyvoid
Based on the accepted answer I wrote a simple Java method that builds the regex from an array of keywords
基于接受的答案，我编写了一个简单的 Java 方法，该方法从一组关键字构建正则表达式
public static String regexIfAllKeywordsExists(String[] keywords) {
StringBuilder sb = new StringBuilder("^");
for (String keyword : keywords) {
sb.append("(?=.*\b");
sb.append(keyword);
sb.append("\b)");
}
sb.append(".+");
return sb.toString();
}
