Java 比较 BigDecimal 是否大于零
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/4164521/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Compare if BigDecimal is greater than zero
提问by Santhosh
How can I compare if BigDecimal
value is greater than zero?
如何比较BigDecimal
值是否大于零?
采纳答案by Jon Skeet
It's as simple as:
这很简单:
if (value.compareTo(BigDecimal.ZERO) > 0)
The documentation for compareTo
actually specifies that it will return -1, 0 or 1, but the more general Comparable<T>.compareTo
method only guarantees less than zero, zero, or greater than zero for the appropriate three cases - so I typically just stick to that comparison.
的文档compareTo
实际上指定它将返回 -1、0 或 1,但更通用的Comparable<T>.compareTo
方法仅保证在适当的三种情况下小于零、零或大于零 - 所以我通常只坚持这种比较。
回答by duffymo
Use compareTo()
function that's built into the class.
使用compareTo()
类中内置的函数。
回答by Anton Bessonov
回答by Rama Krishna
BigDecimal obj = new BigDecimal("100");
if(obj.intValue()>0)
System.out.println("yes");
回答by Satya M
using ".intValue()" on BigDecimal object is not right when you want to check if its grater than zero. The only option left is ".compareTo()" method.
当您想检查它是否大于零时,在 BigDecimal 对象上使用“.intValue()”是不正确的。剩下的唯一选项是“.compareTo()”方法。