javascript jqgrid 如何显示服务器端消息
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jqgrid how to show server side messages
提问by Bhushan
I am using jqGrid
to show data in tabular format, using JSP
and servlet
.
我使用的jqGrid
显示在表格格式的数据,使用JSP
和servlet
。
EDIT
编辑
I want to show errors from server, when operations like insert, update, delete
are performed. (datatype: "xml")
当执行类似操作时,我想显示来自服务器的错误insert, update, delete
。(datatype: "xml")
JQGrid
JQGrid
jQuery("#list10_d").jqGrid({
height:250,
width:600,
url:'Assignment?action=Assign',
datatype: "xml",
colNames:['Sr. No.','PID', 'DATE', 'EMPID'],
colModel:[{name:'srNo',index:'srNo', width:30,sortable:false},
{name:'PID',index:'PID',width:0, sortable:true,editable:false},
{name:'DATE',index:'DATE', width:75,sortable:true,editable:true,editoptions: { dataInit: function(el) { setTimeout(function() { $(el).datepicker({dateFormat:"dd-M-yy",showButtonPanel: true,changeYear: true,changeMonth: true}).attr('readonly','readonly'); }, 200); }}},
{name:'EMPID',index:'EMPID', width:150,sortable:true,editable:true}
],
rowNum:10,
rowList:[10,20,50,100],
pager: '#pager10_d',
sortname: 'PID',
viewrecords: true,
sortorder: "asc",
},
multiselect: true,
editurl: "Assignment?action=Edit",
caption:"Assignment"
} ).navGrid('#pager10_d',{edit:false,add:true,del:false,addtext:'Assign '},
{},
{modal:true,jqModal: false,closeOnEscape:true,savekey: [true,13],closeOnEscape:true, recreateForm: true,width:500,mtype:'POST', url: 'Assignment',editData:{action: 'Assign',PID: function () {return PID;}},
afterSubmit: function (response) {
alert('After Submit \n' +'statusText: '+ response.statusText);
var myInfo = '<div class="ui-state-highlight ui-corner-all">'+
'<span class="ui-icon ui-icon-info" ' +
'style="float: left; margin-right: .3em;"></span>' +
response.statusText + 'Inserted'+
'</div>',
$infoTr = $("#TblGrid_" + $.jgrid.jqID(this.id) + ">tbody>tr.tinfo"),
$infoTd = $infoTr.children("td.topinfo");
$infoTd.html(myInfo);
$infoTr.show();
// display status message to 3 sec only
setTimeout(function () {
$infoTr.slideUp("slow");
}, 5000);
return [true, "", ""]; // response should be interpreted as successful
},
errorTextFormat: function (response) {
alert('Error Text Format: \n' +'statusText: '+ response.statusText);
return '<span class="ui-icon ui-icon-alert" ' +
'style="float:left; margin-right:.3em;"></span>' +
response.statusText;},
{closeOnEscape:true, recreateForm: true,mtype: 'POST',url: 'Assignment',delData: {action: 'Delete',PID: function () {return PID;}}},
{}) ;
Servlet Code
服务程序代码
if(request.getParameter("action").equalsIgnoreCase("Assign"))
{
PID = request.getParameter("PID");
String DATE= request.getParameter("DATE");
String EMPID= request.getParameter("EMPID");
String query = "insert into ASSIGN(PID,DATE,EMPID) values('"+ PID +"','"+ DATE +"','"+ EMPID"')";
boolean b = insert.InsertData(query);
if(b)
{
System.out.println("New record added successfully! : "+query);
response.setContentType("text/xml");
response.setCharacterEncoding("UTF-8");
//response.sendError(200, "success");
response.setStatus(200, "Inserted successfully");
}
else
{
System.out.println("Failed to add Record! : "+query);
response.setContentType("text/xml");
response.setCharacterEncoding("UTF-8");
//response.sendError(399, "not Inserted successfully");
response.setStatus(404, "Error while inserting");
}
}//INSERT
for above example
对于上面的例子
- after
inserting
record from jqgrid, thenNo message is shown
in grid if record isinserted successfully
error Status: 'Unauthorized'. Error code: 401
is shown if servlet fails to insert record in database.
- 之后
inserting
从jqGrid的记录,然后No message is shown
在网格如果记录inserted successfully
error Status: 'Unauthorized'. Error code: 401
如果 servlet 无法在数据库中插入记录,则会显示。
My Question is that:
我的问题是:
- after
inserting
record from jqgrid, if the record is inserted then how should i show message giving information to user that data is inserted. - and how should I give message to user that
Error while inserting
(whicherror code
should i use for this?)
inserting
从 jqgrid 记录后,如果插入了记录,那么我应该如何向用户显示插入数据的信息。- 以及我应该如何向用户发送消息
Error while inserting
(error code
我应该为此使用哪个?)
Thanks in advance.....
提前致谢.....
采纳答案by Oleg
I suggested in the old answerand in another oneto use existing hidden row of grid form (tr.tinfo
) to display information which is not error. Because the answers are not well known I repeat the same information here, but I'll try to explain all more detailed.
我在旧答案和另一个答案中建议使用现有的网格形式隐藏行 ( tr.tinfo
) 来显示不是错误的信息。因为答案并不为人所知,所以我在这里重复相同的信息,但我会尝试更详细地解释所有内容。
First of all it's important to understand which elements has the standard Edit/Add form. Using Developer Tools of IE or Chrome, Firebug or many other tool one can easy find out that the Add/Edit form created by jqGrid contains two hidden rows on top of the form:
首先,了解哪些元素具有标准的编辑/添加表单很重要。使用 IE 或 Chrome、Firebug 或许多其他工具的开发人员工具可以很容易地发现 jqGrid 创建的添加/编辑表单在表单顶部包含两个隐藏行:
The first row will be used per default as the place for error message. One can use errorTextFormat
to customize the information a little.
默认情况下,第一行将用作错误消息的位置。可以使用一点errorTextFormat
来自定义信息。
If the server response contains error HTTP status code (>=400) then the callback errorTextFormat
will be called and you can use
如果服务器响应包含错误 HTTP 状态代码 (>=400),则将调用回调errorTextFormat
,您可以使用
errorTextFormat: function (response) {
return response.responseText;
}
or something like
或类似的东西
errorTextFormat: function (response) {
return '<span class="ui-icon ui-icon-alert" ' +
'style="float:left; margin-right:.3em;"></span>' +
response.responseText;
}
to display error message like
显示错误信息,如
In the same way one can use afterSubmit
callback to display status message after submitting of edited/added data if the server response contains successful HTTP status code. The implementation of afterSubmit
could be about the following
以同样的方式,afterSubmit
如果服务器响应包含成功的HTTP 状态代码,则可以在提交编辑/添加数据后使用回调来显示状态消息。的实施afterSubmit
可能是关于以下
afterSubmit: function (response) {
var myInfo = '<div class="ui-state-highlight ui-corner-all">'+
'<span class="ui-icon ui-icon-info" ' +
'style="float: left; margin-right: .3em;"></span>' +
response.responseText +
'</div>',
$infoTr = $("#TblGrid_" + $.jgrid.jqID(this.id) + ">tbody>tr.tinfo"),
$infoTd = $infoTr.children("td.topinfo");
$infoTd.html(myInfo);
$infoTr.show();
// display status message to 3 sec only
setTimeout(function () {
$infoTr.slideUp("slow");
}, 3000);
return [true, "", ""]; // response should be interpreted as successful
}
The code will display the status message for 3 sec only abd then uses jQuery.slideUpanimation to hide it. It will look like
该代码将仅显示 3 秒的状态消息,然后使用jQuery.slideUp动画将其隐藏。它看起来像
I hope it's what you need.
我希望这是你需要的。
回答by Mark
I have done somthing similar on an edit call to my server so I think this would work in a very similar manner to an add.
我对我的服务器的编辑调用做了类似的事情,所以我认为这与添加的方式非常相似。
On the controller after an edit/delete/add call you would determine if there is a message to be passed to the user and if so pass it via the JSON (XML in your case) back to the grid.
在编辑/删除/添加调用之后的控制器上,您将确定是否有消息要传递给用户,如果是,则通过 JSON(在您的情况下为 XML)将其传递回网格。
Ex
前任
if (infoDialogTrigger) {
return Json(new { success = true, showMessage = true, message = "Updating your Inventory and we are displaying this info box" });
}//if
else {
return Json(new { success = true, showMessage = false, message = "" });
}//else
In your jqGrid you would have your edit/delete/add function:
在您的 jqGrid 中,您将拥有编辑/删除/添加功能:
function EditCollectionItem (rowid, grid){
$(grid).jqGrid('editGridRow', rowid,
{
viewPagerButtons: false,
editData: { },
afterComplete: function (response) {
var DialogVars = $.parseJSON(response.responseText); //parse the string that was returned in responseText into an object
//if there was a failure with the update, or there was information to pass to the user
if (!DialogVars.success || DialogVars.showMessage) {
alert(DialogVars.message);
}
} //afterComplete
}); //$(grid).jqGrid('editGridRow
}//function EditCollectionItem (rowid, grid){
So in the above example if the operation was a failure you could show a message with a success = false
or if the operation was completed but you wanted to pass some extra information to the user you could as well with sucess = true
&& showMessage = true
.
因此,在上面的示例中,如果操作失败,您可以显示带有 a 的消息,success = false
或者如果操作已完成,但您想将一些额外信息传递给用户,您也可以使用sucess = true
&& showMessage = true
。
This is a JSON example of an edit but the concepts and logic should be the same for XML and an add/delete operation.
这是一个编辑的 JSON 示例,但 XML 和添加/删除操作的概念和逻辑应该相同。