Python '没有找到应用程序。要么在视图函数内工作，要么推送应用程序上下文。
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/46540664/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
'No application found. Either work inside a view function or push an application context.'
提问by Omegastick
I'm trying to separate my Flask-SQLAlchemy models into separate files. When I try to run db.create_all()I get No application found. Either work inside a view function or push an application context.
我正在尝试将我的 Flask-SQLAlchemy 模型分成单独的文件。当我尝试跑步时，db.create_all()我得到No application found. Either work inside a view function or push an application context.
shared/db.py:
shared/db.py：
from flask_sqlalchemy import SQLAlchemy
db = SQLAlchemy()
app.py:
app.py：
from flask import Flask
from flask_sqlalchemy import SQLAlchemy
from shared.db import db
app = Flask(__name__)
app.config['SQLALCHEMY_DATABASE_URI'] = 'My connection string'
db.init_app(app)
user.py:
user.py：
from shared.db import db
class User(db.Model):
id = db.Column(db.Integer, primary_key=True)
email_address = db.Column(db.String(300), unique=True, nullable=False)
password = db.Column(db.Text, nullable=False)
回答by Shtlzut
Use with app.app_context()to push an application context when creating the tables.
用于with app.app_context()在创建表时推送应用程序上下文。
app = Flask(__name__)
app.config['SQLALCHEMY_DATABASE_URI'] = 'My connection string'
db.init_app(app)
with app.app_context():
db.create_all()
