wordpress 如何从WordPress中的帖子中获取帖子?

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时间:2020-09-08 11:10:37  来源:igfitidea点击:

How to get post slug from post in WordPress?

wordpress

提问by user1990

I want to get "abc_15_11_02_3" from http://example.com/project_name/abc_15_11_02_3/. How can i do this?

我想从http://example.com/project_name/abc_15_11_02_3/获取“abc_15_11_02_3” 。我怎样才能做到这一点?

回答by Keyur Patel

You can get that using the following methods:

您可以使用以下方法获得它:

<?php $post_slug = get_post_field( 'post_name', get_post() ); ?>

Or You can use this easy code:

或者您可以使用这个简单的代码:

<?php
    global $post;
    $post_slug = $post->post_name;
?>

回答by WisdmLabs

If you want to get slug of the post from the loopthen use:

如果您想从循环中获取帖子的 slug,请使用:

global $post;
echo $post->post_name;


If you want to get slug of the post outside the loopthen use:

如果您想在循环外获取帖子的 slug,请使用:

$post_id = 45; //specify post id here
$post = get_post($post_id); 
$slug = $post->post_name;

回答by Yatin Khullar

You can do this is in many ways like:

您可以通过多种方式执行此操作,例如:

1- You can use Wordpress global variable $post:

1- 您可以使用 Wordpress 全局变量$post

<?php 
global $post;
$post_slug=$post->post_name;
?>

2- Or you can get use:

2-或者你可以使用:

$slug = get_post_field( 'post_name', get_post() );

3- Or get full url and then use the PHP function parse_url:

3- 或者获取完整的 url,然后使用 PHP 函数parse_url

$url      = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";
$url_path = parse_url( $url, PHP_URL_PATH );
$slug = pathinfo( $url_path, PATHINFO_BASENAME );

I hope above methods will help you.

希望以上方法能帮到你。

回答by theRana

Wordpress: Get post/page slug

Wordpress:获取帖子/页面 slug

<?php 
// Custom function to return the post slug
function the_slug($echo=true){
  $slug = basename(get_permalink());
  do_action('before_slug', $slug);
  $slug = apply_filters('slug_filter', $slug);
  if( $echo ) echo $slug;
  do_action('after_slug', $slug);
  return $slug;
}
?>
<?php if (function_exists('the_slug')) { the_slug(); } ?>

回答by Igor Yavych

You can retrieve it from the post object like so:

您可以像这样从 post 对象中检索它:

global $post;
$post->post_name;

回答by hossein naghneh

this simple code worked for me:

这个简单的代码对我有用:

$postId = get_the_ID();
$slug = basename(get_permalink($postId));
echo $slug;

回答by faryal rida

Best option to do this according to WP Codex is as follow.

根据 WP Codex 执行此操作的最佳选择如下。

Use the global variable $post:

使用全局变量 $post:

<?php 
    global $post;
    $post_slug = $post->post_name;
?>

回答by Iisrael

I came across this method and I use it to make div IDs the slug name inside the loop:

我遇到了这种方法,并使用它使 div ID 成为循环内的 slug 名称:

<?php $slug = basename( get_permalink() ); echo $slug;?>

回答by ICG DEVS

use global variable $post

使用全局变量 $post

<?php 
    global $post;
    $post_slug=$post->post_name;
?>

回答by Ivijan Stefan Stipi?

Here is most advanced and updated version what cover many cases:

这是最先进和更新的版本,涵盖了许多情况:

if(!function_exists('the_slug')):
    function the_slug($post_id=false, $echo=true) {
        global $product, $page;

        if(is_numeric($post_id) && $post_id == intval($post_id)) {} else {
            if(!is_object($post_id)){}else if(property_exists($post_id, 'ID')){
                $post_id = $post_id->ID;
            }
            if(empty($post_id) && property_exists($product, 'ID')) $post_id = $product->ID;
            if(empty($post_id)) $post_id =  get_the_ID();

            if(empty($post_id) && property_exists($page, 'ID')) $post_id =  $page->ID;
        }

        if(!empty($post_id))
            $slug = basename(get_permalink($post_id));
        else
            $slug = basename(get_permalink());
        do_action('before_slug', $slug);
        $slug = apply_filters('slug_filter', $slug);
        if( $echo ) echo $slug;
        do_action('after_slug', $slug);
        return $slug;
      }
endif;

This is collections from the best answers and few my updates.

这是最佳答案的集合,我的更新很少。