Java 如何使用 Webdriver Selenium 获取“style”元素的值
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How to Using Webdriver Selenium to get the value of "style" element
提问by Sohaib Maroof
I want to check whether the value of a style element is greater than a particular value (i.e., is left > 666px ?), but I am unable to get ahold of the value.
我想检查样式元素的值是否大于特定值（即，是否为 left > 666px ？），但我无法获得该值。
Here is the HTML code of the style that I want to capture:
这是我要捕获的样式的 HTML 代码：
<pre><span id="da2c" style="left: 666px; top: 27px;"></pre>
I am using this code to try to print its value, but it's not printing:
我正在使用此代码尝试打印其值，但未打印：
System.out.print(driver.findElement(By.id("da1c")).findElement(By.cssSelector("span")).getAttribute("style"));
I want something like this:
我想要这样的东西：
if ((driver.findElement(By.id("da1c")).findElement(By.cssSelector("span")).getAttribute("style")).value> 700) {
System.out.println("value exceeding")
}
回答by ddavison
If you execute .getAttribute("style")on that span, you will recieve a String.
如果您.getAttribute("style")在该跨度上执行，您将收到一个字符串。
left: 666px; top: 27px;
You can use string manipulation to fetch a particular style.
left: 666px; top: 27px;
您可以使用字符串操作来获取特定样式。
Alternatively, you can execute some javascript magic using the JavaScriptExecutor, and fetching the leftvalue directly by
或者，您可以使用 JavaScriptExecutor 执行一些 javascript 魔术，并left直接通过
String script = "var thing = window.document.getElementById('da2c');
window.document.defaultView.getComputedStyle(thing, null).getPropertyValue('left');";
and then check it from there.
然后从那里检查它。
回答by Anirudh
You may capture the Computed Css value as shown in the firebug screenshot below:
您可以捕获 Computed Css 值，如下面的萤火虫屏幕截图所示：
like this:
像这样：
WebDriver web = new FirefoxDriver(;
String visibility = web.findElement(By.xpath("//your xpath")).getCssValue("display");
回答by Максим Скрипченко
driver.findElement(By.locator( yourLocator )).getAttribute( requiredAttribute )
It will return String
它将返回字符串
