C语言 如何使用 C 将二进制字符串转换为十六进制？
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How do I convert a binary string to hex using C?
提问by chris
How do I convert an 8-bit binary string (e.g. "10010011") to hexadecimal using C?
如何使用 C 将 8 位二进制字符串（例如“10010011”）转换为十六进制？
回答by Ben
#include <stdlib.h>
strtol("10010011", NULL, 2);
回答by CyberDem0n
Something like that:
类似的东西：
char *bin="10010011";
char *a = bin;
int num = 0;
do {
int b = *a=='1'?1:0;
num = (num<<1)|b;
a++;
} while (*a);
printf("%X\n", num);
回答by ughoavgfhw
void binaryToHex(const char *inStr, char *outStr) {
// outStr must be at least strlen(inStr)/4 + 1 bytes.
static char hex[] = "0123456789ABCDEF";
int len = strlen(inStr) / 4;
int i = strlen(inStr) % 4;
char current = 0;
if(i) { // handle not multiple of 4
while(i--) {
current = (current << 1) + (*inStr - '0');
inStr++;
}
*outStr = hex[current];
++outStr;
}
while(len--) {
current = 0;
for(i = 0; i < 4; ++i) {
current = (current << 1) + (*inStr - '0');
inStr++;
}
*outStr = hex[current];
++outStr;
}
*outStr = 0; // null byte
}
回答by Sean
How about
怎么样
char *binary_str = "10010011";
unsigned char hex_num = 0;
for (int i = 0, char *p = binary_str; *p != '##代码##'; ++p, ++i)
{
if (*p == '1' )
{
hex_num |= (1 << i);
}
}
and now you've got hex_num and you can do what you want with it. Note that you might want to verify the length of the input string or cap the loop at the number of bits in hex_num.
现在你有了 hex_num 并且你可以用它做你想做的事。请注意，您可能希望验证输入字符串的长度或将循环限制在 hex_num 中的位数。
