xml 如何在 XSLT 中获得以下兄弟
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How to get the following sibling in XSLT
提问by Tintin81
I am fairly new to XSLT and this is my XML:
我对 XSLT 还很陌生，这是我的 XML：
<projects>
<project>
<number>1</number>
<title>Project X</title>
</project>
<project>
<number>2</number>
<title>Project Y</title>
</project>
<project>
<number>3</number>
<title>Project Z</title>
</project>
</projects>
If I have one project and want to get the sibling that follows it, how can I do that?
如果我有一个项目并且想要获得跟随它的兄弟姐妹，我该怎么做？
This code doesn't seem to work for me:
这段代码似乎对我不起作用：
/projects[title="Project X"]/following-sibling
回答by Dimitre Novatchev
This is actually a completely XPath question.
这实际上是一个完全 XPath 的问题。
Use:
使用：
/*/project[title = 'Project X']/following-sibling::project[1]
This selects any first following sibling Projectof any Projectelement that is a child of the top element in the XML document and the string value of at least of one of its titlechildren is the string "Project X".
这将选择作为 XML 文档中顶部元素的子元素Project的任何Project元素的任何第一个后续兄弟元素，并且其至少一个子元素的字符串值title是 string "Project X"。
XSLT - based verification:
基于 XSLT 的验证：
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output omit-xml-declaration="yes" indent="yes"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:copy-of select=
"/*/project[title = 'Project X']/following-sibling::project[1]"/>
</xsl:template>
</xsl:stylesheet>
When this transformation is applied on the provided XML document:
当此转换应用于提供的 XML 文档时：
<projects>
<project>
<number>1</number>
<title>Project X</title>
</project>
<project>
<number>2</number>
<title>Project Y</title>
</project>
<project>
<number>3</number>
<title>Project Z</title>
</project>
</projects>
the XPath expression is evaluated and the correctly-selected element is copied to the output:
计算 XPath 表达式并将正确选择的元素复制到输出：
<project>
<number>2</number>
<title>Project Y</title>
</project>
