C++ 初始化 QList 的正确方法是什么？
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What is the right way to initialize a QList?
提问by msgmaxim
What is the right way to initialize QList? I want to make this code shorter:
初始化 QList 的正确方法是什么？我想让这段代码更短：
QSplitter splitter;
QList<int> list;
list.append(1);
list.append(1);
splitter.setSizes(list);
But when I use initialization from std::list, it doesn't seem be working:
但是当我从 std::list 使用初始化时，它似乎不起作用：
splitter.setSizes(QList<int>::fromStdList(std::list<int>(1, 1)));
In latter case, the splitter seems to divide in ratio 1:0.
在后一种情况下，分路器似乎以 1:0 的比例进行分频。
回答by lpapp
You could use the following code:
您可以使用以下代码：
QList<int> list = QList<int>() << 1 << 1;
or initializer list with C++11:
或 C++11 的初始化列表：
QList<int> list({1, 1});
You can enable the latter with the -std=c++0x or -std=c++11 option for gcc. You will also need the relevant Qt version for that where initializer list support has been added to the QList constructor.
您可以使用 gcc 的 -std=c++0x 或 -std=c++11 选项启用后者。您还需要相关的 Qt 版本，因为在 QList 构造函数中添加了初始化列表支持。
回答by Tomaz Canabrava
Never use the QList<int>() << 1 << 1;variant, as it's really slow.
use always the list({1, 1})variant.
永远不要使用QList<int>() << 1 << 1;变体，因为它真的很慢。始终使用list({1, 1})变体。
source: https://www.angrycane.com.br/en/2018/06/19/speeding-up-cornercases/
来源：https: //www.angrycane.com.br/en/2018/06/19/speeding-up-cornercases/
