如何防止重复项 listView C#
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How prevent duplicate items listView C#
提问by Vincenzo Lo Palo
I am using Windows Forms. With this code I add items to listViewfrom comboBox.
我正在使用Windows Forms. 使用此代码，我将项目添加到listViewfrom comboBox。
ListViewItem lvi = new ListViewItem();
lvi.Text = comboBox1.Text;
lvi.SubItems.Add("");
lvi.SubItems.Add("");
lvi.SubItems.Add("");
lvi.SubItems.Add("")
if (!listView1.Items.Contains(lvi))
{
listView1.Items.Add(lvi);
}
I need prevent duplicate items but not work, How Can I solve this?
我需要防止重复项目但不起作用，我该如何解决？
采纳答案by Larry
You should be using ContainsKey(string key)instead of Contains(ListViewItem item)
你应该使用ContainsKey(string key)而不是Contains(ListViewItem item)
var txt = comboBox1.Text;
if (!listView1.Items.ContainsKey(txt))
{
lvi.Text = txt;
// this is the key that ContainsKey uses. you might want to use the value
// of the ComboBox or something else, depending the combobox is freetext
// or regarding your scenario.
lvi.Name = txt;
lvi.SubItems.Add("");
lvi.SubItems.Add("");
lvi.SubItems.Add("");
lvi.SubItems.Add("");
listView1.Items.Add(lvi);
}
回答by Parimal Raj
The ListView class provides a few way to check if an item exists:
ListView 类提供了几种检查项目是否存在的方法：
ContainsOnItems collection, andFindItemWithTextmethods
It can be used like :
它可以像这样使用：
// assuming you had a pre-existing item
ListViewItem item = ListView1.FindItemWithText("item_key");
if (item == null)
{
// item does not exist
}
// you can also use the overloaded method to match subitems
ListViewItem item = ListView1.FindItemWithText("sub_item_text", true, 0);
回答by PhonicUK
if (!listView1.Items.Any(i => i.text == lvi.text))
{
listView1.items.Add(lvi)
}
I'm just guessing on the text property, but I'm pretty sure that's there.
我只是在猜测 text 属性，但我很确定它就在那里。
Alternatively - just have a List<string>and use it as a data source for your list.
或者 - 只需拥有一个List<string>并将其用作列表的数据源。
回答by codegasm
This code worked for me:
这段代码对我有用：
if(DialogResult.OK == fileDialogue.ShowDialog())
{
foreach (var v in fileDialogue.FileNames)
{
if (listView.FindItemWithText(v) == null)
{
listView.Items.Add(v);
}
else
//Throw error message
回答by sgupta
String csVal = Value;
ListViewItem csItem = new ListViewItem(csVal);
if (!listViewABC.Items.ContainsKey(csVal))
{
csItem.Name = csVal;
listViewABC.Items.Add(csItem );
}
