C语言 如何检查 int var 是否包含特定数字
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How to check if a int var contains a specific number
提问by c5754272
How to check if a int var contains a specific number
如何检查 int var 是否包含特定数字
I cant find a solution for this. For example: i need to check if the int 457 contains the number 5 somewhere.
我找不到解决方案。例如：我需要检查 int 457 是否在某处包含数字 5。
Thanks for your help ;)
谢谢你的帮助 ;）
回答by matt.dolfin
457 % 10 = 7 *
457 / 10 = 45
45 % 10 = 5 *
45 / 10 = 4
4 % 10 = 4 *
4 / 10 = 0 done
Get it?
得到它？
Here's a C implementation of the algorithm that my answer implies. It will find any digit in any integer. It is essentially the exact same as Shakti Singh's answer except that it works for negative integers and stops as soon as the digit is found...
这是我的答案所暗示的算法的 C 实现。它将在任何整数中找到任何数字。它本质上与 Shakti Singh 的答案完全相同，除了它适用于负整数并在找到数字后立即停止......
const int NUMBER = 457; // This can be any integer
const int DIGIT_TO_FIND = 5; // This can be any digit
int thisNumber = NUMBER >= 0 ? NUMBER : -NUMBER; // ?: => Conditional Operator
int thisDigit;
while (thisNumber != 0)
{
thisDigit = thisNumber % 10; // Always equal to the last digit of thisNumber
thisNumber = thisNumber / 10; // Always equal to thisNumber with the last digit
// chopped off, or 0 if thisNumber is less than 10
if (thisDigit == DIGIT_TO_FIND)
{
printf("%d contains digit %d", NUMBER, DIGIT_TO_FIND);
break;
}
}
回答by Yhrn
Convert it to a string and check if the string contains the character '5'.
将其转换为字符串并检查该字符串是否包含字符“5”。
回答by Shakti Singh
int i=457, n=0;
while (i>0)
{
n=i%10;
i=i/10;
if (n == 5)
{
printf("5 is there in the number %d",i);
}
}
