如何在 Windows 中获取批处理脚本的路径？
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How to get the path of the batch script in Windows?
提问by Misha Moroshko
I know that %0contains the full path of the batch script, e.g. c:\path\to\my\file\abc.bat
我知道%0包含批处理脚本的完整路径，例如c:\path\to\my\file\abc.bat
I would pathto be equal to c:\path\to\my\file
我会path等于c:\path\to\my\file
How could I achieve that ?
我怎么能做到这一点？
回答by Dean Harding
%~dp0will be the directory. Here's some documentation on all of the path modifiers. Fun stuff :-)
%~dp0将是目录。这是有关所有路径修饰符的一些文档。好玩的东西 ：-）
To remove the final backslash, you can use the :n,msubstring syntax, like so:
要删除最后的反斜杠，您可以使用:n,m子字符串语法，如下所示：
SET mypath=%~dp0
echo %mypath:~0,-1%
I don't believe there's a way to combine the %0syntax with the :~n,msyntax, unfortunately.
不幸的是，我不相信有一种方法可以将%0语法与:~n,m语法结合起来。
回答by duan
You can use following script to get the path without trailing "\"
您可以使用以下脚本获取不带尾随“\”的路径
for %%i in ("%~dp0.") do SET "mypath=%%~fi"
回答by Arnaud
%~dp0may be a relative path.
To convert it to a full path, try something like this:
%~dp0可能是相对路径。要将其转换为完整路径，请尝试以下操作：
pushd %~dp0
set script_dir=%CD%
popd
回答by Hayz
You can use %~dp0, d means the drive only, p means the path only, 0 is the argument for the full filename of the batch file.
您可以使用%~dp0, d 表示仅驱动器， p 表示仅路径， 0 是批处理文件的完整文件名的参数。
For example if the file path was C:\Users\Oliver\Desktop\example.bat then the argument would equal C:\Users\Oliver\Desktop\, also you can use the command set cpath=%~dp0 && set cpath=%cpath:~0,-1%and use the %cpath%variable to remove the trailing slash.
例如，如果文件路径是 C:\Users\Oliver\Desktop\example.bat，则参数将等于 C:\Users\Oliver\Desktop\，您也可以使用该命令set cpath=%~dp0 && set cpath=%cpath:~0,-1%并使用该%cpath%变量删除尾部斜杠。
回答by Uddalak Biswas
%cd%will give you the path of the directory from where the script is running.
%cd%将为您提供脚本运行所在目录的路径。
Just run:
赶紧跑：
echo %cd%
回答by Ruel
That would be the %CD%variable.
那将是%CD%变量。
@echo off
echo %CD%
%CD%returns the current directory the batch script is in.
%CD%返回批处理脚本所在的当前目录。
回答by Jonas
I am working on a Windows 7 machine and I have ended up using the lines below to get the absolute folder path for my bash script.
我在 Windows 7 机器上工作，我最终使用下面的行来获取我的 bash 脚本的绝对文件夹路径。
I got to this solution after looking at http://www.linuxjournal.com/content/bash-parameter-expansion.
在查看http://www.linuxjournal.com/content/bash-parameter-expansion后，我得到了这个解决方案。
#Get the full aboslute filename.
filename=##代码##
#Remove everything after \. An extra \ seems to be necessary to escape something...
folder="${filename%\*}"
#Echo...
echo $filename
echo $folder
