php 注意：尝试获取非对象的属性
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Notice: Trying to get property of non-object
提问by talhaMalik22
i am facing this problem here. i want to show item's name by getting its item id from another table. following is the code
i am having problem when i try to show name using ".$obj[0]->name." in the first line of the for loop.
我在这里面临这个问题。我想通过从另一个表中获取项目 ID 来显示项目的名称。以下是
当我尝试使用“.$obj[0]->name”显示名称时遇到问题的代码。在 for 循环的第一行。
$objClass = array();
$objClass1 = array();
$obj= array();
$object = new product();
$objLogic = new customerLogic();
$objLogic1 = new customerLogic();
$objL= new productLogic();
$objClass[0]= new stdClass;
$objClass1[0]= new stdClass;
$obj[0]= new stdClass;
$objClass[0]->custId = $_GET['id'];
$objClass1[0]->custId = $_GET['id'];
$objClass = $objLogic->getSaleRecord_customer($objClass[0]);
$objClass1 = $objLogic1->getName_customer($objClass1[0]);
$object->itemId = $objClass[0]->itemId;
$obj =$objL->getName_product($object->itemId);
// echo $objClass1[0]->firstName;
$i=1;
foreach($objClass as $customer ) {
echo "<tr><td class=\"inner_text\">$customer->reciept</td><td align=\"center\">".$obj[0]->name."</td>";
echo "<td align=\"center\">".$objClass1[0]->firstName." ".$objClass1[0]->lastName."</td><td align=\"center\">";
echo "$customer->weight</td>
<td align=\"center\">$customer->costPerKg</td>
<td align=\"center\">$customer->cost</td>
<td align=\"center\">$customer->payed</td>
<td align=\"center\">$customer->remaining</td></tr>";
$i++;
}
?>
</table>
采纳答案by Milad Naseri
Are you completely sure that $objL->getName_product($object->itemId);yields an object?
你完全确定这会$objL->getName_product($object->itemId);产生一个对象吗？
Could you verify that?
你能验证一下吗？
I think the return value of $objL->getName_product($object->itemId);is not what you think it is.
我认为的返回值$objL->getName_product($object->itemId);不是您认为的那样。
You can check it by print_r($objL->getName_product($object->itemId));which will give you a printout of the contents of that functions output.
您可以通过print_r($objL->getName_product($object->itemId));它来检查它，它将为您提供该函数输出内容的打印输出。
Or maybe you are unintentionally overriding the contents of $obj?
或者您可能无意中覆盖了$obj?
回答by Pekka
You are overwriting $obj:
您正在覆盖$obj：
$obj =$objL->getName_product($object->itemId);
