bash 我收到错误“array.sh：3：array.sh：语法错误：”（“意外”
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I am getting error "array.sh: 3: array.sh: Syntax error: "(" unexpected"
提问by Mistu4u
I have written the following code:
我编写了以下代码：
#!/bin/bash
#Simple array
array=(1 2 3 4 5)
echo ${array[*]}
And I am getting error: array.sh: 3: array.sh: Syntax error: "(" unexpected
我收到错误：array.sh：3：array.sh：语法错误：“（”意外
From what I came to know from Google, that this might be due to the fact that Ubuntu is now not taking "#!/bin/bash" by default... but then again I added the line but the error is still coming.
根据我从 Google 了解到的情况，这可能是因为 Ubuntu 现在默认不采用“#!/bin/bash”...但我再次添加了该行，但错误仍然存在。
Also I have tried by executing bash array.shbut no luck! It prints blank.
我也尝试过执行bash array.sh但没有运气！它打印空白。
My Ubuntu version is: Ubuntu 14.04
我的 Ubuntu 版本是：Ubuntu 14.04
回答by Keith Thompson
Given that script:
鉴于该脚本：
#!/bin/bash
#Simple array
array=(1 2 3 4 5)
echo ${array[*]}
and assuming:
并假设：
- It's in a file in your current directory named
array.sh; - You've done
chmod +x array.sh; - You have a sufficiently new version of bash installed in
/bin/bash(you report that you have 4.3.8, which is certainly new enough); and - You execute it correctly
- 它位于您当前目录中名为
array.sh;的文件中。 - 你已经完成了
chmod +x array.sh； - 您安装了足够新的 bash 版本
/bin/bash（您报告说您有 4.3.8，这当然足够新）；和 - 你正确地执行它
then that should work without any problem.
那么这应该没有任何问题。
If you execute the script by typing
如果您通过键入来执行脚本
./array.sh
the system will pay attention to the #!/bin/bashline and execute the script using /bin/bash.
系统会注意该#!/bin/bash行并使用/bin/bash.
If you execute it by typing something like:
如果您通过键入以下内容来执行它：
sh ./array.sh
then it will execute it using /bin/sh. On Ubuntu, /bin/shis typically a symbolic link to /bin/dash, a Bourne-like shell that doesn'tsupport arrays. That will give you exactly the error message that you report.
然后它将使用/bin/sh. 在 Ubuntu 上，/bin/sh通常是指向 的符号链接/bin/dash，一个不支持数组的类似 Bourne 的 shell 。这将准确地为您提供您报告的错误消息。
The shell used to execute a script is not affected by which shell you're currently using or by which shell is configured as your login shell in /etc/passwdor equivalent (unless you use the sourceor .command).
用于执行脚本的 shell 不受您当前使用的 shell 或配置为登录 shell/etc/passwd或等效的shell （除非您使用sourceor.命令）的影响。
In your own answer, you say you fixed the problem by using chshto change your default login shell to /bin/bash. That by itself should not have any effect. (And /bin/bashis the default login shell on Ubuntu anyway; had you changed it to something else previously?)
在您自己的回答中，您说您通过使用chsh将默认登录 shell 更改为/bin/bash. 这本身不应该有任何影响。（/bin/bash无论如何都是Ubuntu上的默认登录shell；您之前是否将其更改为其他内容？）
What must have happened is that you changed the command you use from sh ./array.shto ./array.shwithout realizing it.
什么是必须发生的是，你改变你使用命令sh ./array.sh来./array.sh而不自知。
Try running sh ./array.shand see if you get the same error.
尝试运行sh ./array.sh，看看是否出现相同的错误。
回答by Fabien Thetis
Instead of using sh to run the script,
而不是使用 sh 来运行脚本，
try the following command:
尝试以下命令：
bash ./array.sh
回答by Mistu4u
I solved the problem miraculously. In order to solve the issue, I found a link where it was described to be gone by using the following code. After executing them, the issue got resolved.
我奇迹般地解决了这个问题。为了解决这个问题，我找到了一个链接，它被描述为使用以下代码消失了。执行它们后，问题得到解决。
chsh -s /bin/bash adhikarisubir
grep ^adhikarisubir /etc/passwd
FYI, "adhikarisubir" is my username.
仅供参考，“adhikarisubir”是我的用户名。
After executing these commands, bash array.shproduced the desired result.
执行bash array.sh完这些命令后，就产生了想要的结果。
