C++ 无法转换大括号括起来的初始化列表
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Cannot convert Brace-enclosed initializer list
提问by user3481693
I declare a table of booleans and initialize it in main()
我声明了一个布尔值表并将其初始化 main()
const int dim = 2;
bool Table[dim][dim];
int main(){
Table[dim][dim] = {{false,false},{true,false}};
// code
return 0;
}
I use mingwcompiler and the builder options are g++ -std=c++11.
The error is
我使用mingw编译器，构建器选项是 g++ -std=c++11. 错误是
cannot convert brace-enclosed initializer list to 'bool' in assignment`
无法将大括号括起来的初始值设定项列表转换为赋值中的“bool”
回答by Some programmer dude
Arrays can only be initialized like that on definition, you can't do it afterwards.
数组只能像定义那样初始化，之后就不能再做。
Either move the initialization to the definition, or initialize each entry manually.
要么将初始化移动到定义，要么手动初始化每个条目。
回答by user3488743
First, you are trying to assign a concrete element of array instead assigning the full array. Second, you can use initializer list only for initialization, and not for assignment.
首先，您试图分配数组的具体元素而不是分配完整的数组。其次，您只能将初始化列表用于初始化，而不能用于赋值。
Here is correct code:
这是正确的代码：
bool Table = {{false,false},{true,false}};
回答by Ankur
You can use memset(Table,false,sizeof(Table))for this.it will work fine.
您可以memset(Table,false,sizeof(Table))为此使用它。它会正常工作。
Here is your complete code
这是您的完整代码
#include <iostream>
#include<cstring>
using namespace std;
const int dim = 2;
bool Table[dim][dim];
int main(){
memset(Table,true,sizeof(Table));
cout<<Table[1][0];
// code
return 0;
}
